9. Distribute the expression -3(-8b-9)
2 answers:
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Answer:
A)
B)
C) for n = 2
= 1
for n = 3
= 3
for n = 4
= 8
for n = 5
= 19
Step-by-step explanation:
A) A recurrence relation for the number of bit strings of length n that contain a pair of consecutive Os can be represented below
if a string (n ) ends with 00 for n-2 positions there are a pair of consecutive Os therefore there will be : strings
therefore for n ≥ 2
The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os
b ) The initial conditions
The initial conditions are :
C) The number of bit strings of length seven containing two consecutive 0s
here we apply the re occurrence relation and the initial conditions
for n = 2
= 1
for n = 3
= 3
for n = 4
= 8
for n = 5
= 19
The volume of a cube = e^3
e = a single edge of the cube.
Area of a square = a^2
a = a single side of the square.
The volume of our cube = 13 ft^3
e = = 2.35 ft
The area of our square = 4 ft^2
a = = 2 ft
The edge of our cube is greater than the length of our square's side.
The poster will lie flat in the box.