What is the prime factorization of 450
1 answer:
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Answer:
see explanation
Step-by-step explanation:
is in the fourth quadrant
Where sin and tan are < 0 , cos > 0
The related acute angle is 2π - =
Hence
sin([ ) = - sin(
) = -
= -
cos() = cos(
) =
tan(= - tan(
= - 1
Answer:
Low Q1 Median Q3 High
6 9 11 12.5 14
The interquartile range = 3.5
Step-by-step explanation:
Given that:
Consider the following ordered data. 6 9 9 10 11 11 12 13 14
From the above dataset, the highest value = 14 and the lowest value = 6
The median is the middle number = 11
For Q1, i.e the median of the lower half
we have the ordered data = 6, 9, 9, 10
here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.
i.e
median =
median =
median = 9
Q3, i.e median of the upper half
we have the ordered data = 11 12 13 14
The same use case is applicable here.
Median =
Median =
Median = 12.5
Low Q1 Median Q3 High
6 9 11 12.5 14
The interquartile range = Q3 - Q1
The interquartile range = 12.5 - 9
The interquartile range = 3.5
Hi there! :)
4x=-36
Divide both sides by 4 in order to isolate x:
x=-9
Hope this helps you and have a nice day!
~Just a joyful teen