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2 years ago

How do you do this i totaly forgot.

Mathematics

1 answer:

vagabundo [1.1K]2 years ago

5 0

Step-by-step explanation:

7^2+8^2=113

Then square root 113 which is 10.63 to 2.d.p

So x=10.63

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Which sphere has a volume of 0.288Pi in.3? A sphere with radius 0.4 inches. A sphere with radius 0.5 inches. A sphere with radiu

worty [1.4K]

C. A sphere with radius 0.6 inches.

Here is why:

The equation for the volume of a sphere is:

$V=\frac{4}{3} \pi r^3$

We can plug in and solve.

$V=\frac{4}{3}*\pi *0.6*0.6*0.6$

We will multiply everything but leave the 3 to divide later.

So...

$4*\pi *0.6*0.6*0.6=0.864\pi$

Divide by 3.

$0.864\pi /3=$

0.288π

5 0

2 years ago

Read 2 more answers

Solve the following equation. X cubed minus 6X squared plus 6X equals zero

anyanavicka [17]

We have to solve this equation:

$x^3-6x^2+6x=0$

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

$\begin{gathered} x^3-6x^2+6x=0 \\ x(x^2-6x+6)=0 \end{gathered}$

Now we can find the roots of the quadratic polynomial as:

$\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}$

Then, the solutions to the equation are:

x = 0

x = 3 - √3

x = 3 + √3

4 0

1 year ago

Which expression has the same value as 3,648 - 1,223? A. 3,000 - 1,000 + 40 - 20 + 8 - 3 + 6 - 2 B. 3,000 - 1,000 + 600 - 200 +

natulia [17]

Answer:

Step-by-step explanation:

3000-1000 = 2000

600-200 = + 400

40 - 20 = + 20

8 - 3 = + 5

7 0

3 years ago

A capacitor has plates of area

kumpel [21]

Answer:

6.1*10^-6

Step-by-step explanation:

Acellus

6 0

3 years ago

What are the real and complex solutions of the polynomial equation? x^3-64=0

Marrrta [24]

Answer:

Step-by-step explanation:

A difference of two perfect cubes, x^3 - y^3 can be factored into

(x-y) • (x^2 +xy +y^2) =0 equation 1

x ^3 - 64 = 0

(x)^3 - (4)^3 = 0 equation 2

Now substituting equation 2 into equation 1, we get

(x-4) (x^2+(x).(4) +(4)^2) = 0

(x-4) (x^2+4x+16) = 0

so the solutions are

1) x - 4 =0

x=4

x^2 + 4x + 16 = 0

By using the quadratic formula we get the followig solutions:

- B ± √ B2-4AC

x = ————————

x =(-4-√-48)/2=-2-2i√ 3 = -2.0000-3.4641i

x =(-4+√-48)/2=-2+2i√ 3 = -2.0000+3.4641i

4 0

3 years ago