Answer:
Tienes 3 números, "x", "y", "z"
=> El primero es 20 unidades menor que el segundo:
El primero es "x", y el segundo es "y", entonces:
x = y - 20
=> El tercero es igual a la suma de los dos primeros:
El tercero es "z", entonces:
z = x + y
z = (y - 20) + y
z = 2y - 20
=> Entre los tres suman 120
x + y + z = 120
y - 20 + y + 2y - 20 = 120
4y - 40 = 120
4y = 160
y = 40
Si y = 40, entonces:
x = y - 20
x = 20
Además, z = 2y - 20
z= 60
RPTA:
x=20
y=40
z=60
Step-by-step explanation:
Answer:
This is easy -- it's just a list of steps. At this level, the problems are pretty simple.
Let's just do one, then I'll write out the list of steps for you.
Find the inverse of f( x ) = -( 1 / 3 )x + 1
STEP 1: Stick a "y" in for the "f(x)" guy:
y = -( 1 / 3 )x + 1
STEP 2: Switch the x and y
( because every (x, y) has a (y, x) partner! ):
x = -( 1 / 3 )y + 1
STEP 3: Solve for y:
x = -( 1 / 3 )y + 1 ... multiply by 3 to ditch the fraction ... 3x = -y + 3 ... ditch the +3 ... subtract 3 from both sides ... 3x - 3 = -y ... multiply by -1 ... -3x + 3 = y ... y = -3x + 3
STEP 4: Stick in the inverse notation, f^( -1 )( x )
f^( -1 )( x ) = -3x + 3
Step-by-step explanation:
Answer:
5 is the hight
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
Answer:
9 answer ok like floow on
