<span>Lithium and Sodium both have their last elections added to s subshells. All alkali and alkali earth metals have their last electrons placed in s subshells.</span>
Answer:
5 × 10^-4 L
Explanation:
The equation of the reaction is;
2KClO3 = 2KCl + 3O2
Number of moles of KClO3 = 13.5g/122.5 g / mol = 0.11 moles
From the stoichiometry of the reaction;
2 moles of KClO3 yields 3 moles of O2
0.11 moles of KClO3 yields 0.11 × 3/2 = 0.165 moles of oxygen gas
From the ideal gas equation;
PV= nRT
P= 85.4 × 10^4 KPa
V=?
n= 0.165
R= 8.314 J K-1 mol-1
T= 40+273 = 313K
V= 0.165 ×8.134 × 313/85.4 × 10^4
V=429.4/85.4 × 10^4
V= 5 × 10^-4 L
Answer:
Actual yield: 86.5 grams.
Explanation:
How many moles of formula units in 95 grams of calcium carbonate
?
Refer to a modern periodic table for relative atomic mass data:
- Ca: 40.078;
- C: 12.011;
- O: 15.999.
Formula mass of
:
.
.
How many moles of
will be produced?
The coefficient in front of
in the chemical equation is the same as that in front of
. That is:
.
.
What's the theoretical yield of calcium chloride? In other words, what's the mass of
of
?
Again, refer to a periodic table for relative atomic data:
.
.
What's the actual yield of calcium chloride?
.
.
Neutral charges and are found in the center? I'm not sure for the last answer