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Gala2k [10]
3 years ago
13

The concentration of ionic substances is important for the heart to beat. Your heart responds to electrical impulses that travel

through heart cells that are made up mostly of water. Which properties of ionic compounds are important to support this function?
Chemistry
2 answers:
Pavel [41]3 years ago
4 0

Answer is: conductivity in solution  and solubility in water.

Ionic compounds conduct electricity, because it dissociate in ions and ions conduct electicity.

Ionic substances dissociate in water on cations and anions. For example, dissociation of potassium chloride in water: KCl(aq) → K⁺(aq) + Cl⁻(aq).

Ionic compounds (most of the salts, strong acids and bases) dissolve in water because an ion-dipole interactions.

An ion-dipole is electrostatic interaction between a charged ion (cations and anions) and a molecule that has a dipole (in this example water).

Dipole is a separation of positive and negative charges. In water, hydrogen has positive and oxygen has negative charge.

VladimirAG [237]3 years ago
4 0

Answer: conductivity in solution  and solubility in water.

Explanation:

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Age
cupoosta [38]

Answer:

Option (2)

Explanation:

Since the amount of each sample is the same, we are looking for the metal with the greatest density, which is copper.

5 0
2 years ago
13.0 g NaHSO4 is dissolved in water to make a 2.00 L solution what is the molarité
Sati [7]

Answer:

0.054 M

Explanation:

1 mol NaHSO4 -> 120 g

                   x    ->13 g

x= 0.108 mol NaHSO4

M= mol solute/ L solution

M= 0.108 mol NaHSO4/ 2.00L

M= 0.054 M

8 0
3 years ago
New questionWhat mass of calcium chloride (CaCl₂) would beproduced from the reaction of 125.9 g of hydrochloriacid (HCI) with ex
marshall27 [118]

Answer:

191.6 g of CaCl₂.

Explanation:

What is given?

Mass of HCl = 125.9 g.

Molar mass of CaCl₂ = 110.8 g/mol.

Molar mass of HCl = 36.4 g/mol.

Step-by-step solution:

First, we have to state the chemical equation. Ca(OH)₂ react with HCl to produce CaCl₂:

Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O.

Now, let's convert 125.9 g of HCl to moles using the given molar mass (remember that the molar mass of a compound can be found using the periodic table). The conversion will look like this:

125.9\text{ g HCl}\cdot\frac{1\text{ mol HCl}}{36.4\text{ g HCl}}=3.459\text{ moles HCl.}

Let's find how many moles of CaCl₂ are being produced by 3.459 moles of HCl. You can see in the chemical equation that 2 moles of HCl reacted with excess Ca(OH)₂ produces 1 mol of CaCl₂, so we state a rule of three and the calculation is:

3.459\text{ moles HCl}\cdot\frac{1\text{ mol CaCl}_2}{2\text{ moles HCl}}=1.729\text{ moles CaCl}_2.

The final step is to find the mass of CaCl₂ using the molar mass of CaCl₂. This conversion will look like this:

1.729\text{ moles CaCl}_2\cdot\frac{110.8\text{ g CaCl}_2}{1\text{ mol CaCl}_2}=191.6\text{ g CaCl}_2.

The answer would be that we're producing a mass of 191.6 g of CaCl₂.

4 0
1 year ago
You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y
lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = age of sample  = 6 days

a = initial amount of the reactant  =  1 g

a - x = amount left after decay process   = 0.2 g

a) to find the rate constant

6=\frac{2.303}{k}\log\frac{1.0}{0.2}

k=\frac{2.303}{6}\log\frac{1.0}{0.2}

k=0.268days^{-1}

b) for completion of half life:  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days

The half life is 2.58 days

3 0
3 years ago
A stone is tied to a 0.85-meter cord. it is swung in a circle at a constant rate of 6.0 m/s. what is the centripetal acceleratio
Elan Coil [88]
The correct answer is 42. I know this answer is right because i have already turned my assignment in and got it right.
4 0
3 years ago
Read 2 more answers
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