The first step is to represent the vectors shown in the image in Cartesian coordinates.
For the vector C we have a magnitude of 4.8 and an angle 22 ° with the axis -y (direction j)
To write this vector in Cartesian coordinates we must find its component in x (address i) and in the y axis.

So:

For Vector B we have a magnitude of 5.6 and an angle of 33 with the -x axis (-i direction)
So:

So:

Finally the sum of B + C is made component by component in the following way:

Finally the magnitude of f is:

| F | = 8.04
Answer:
Cape Point lighthouse
Explanation:
The lighthouse is located South of Cape Town, at a point where boats turn to go around the tip of Africa.
The new lighthouse has the most powerful light of all the lighthouses in South Africa, with a power of 10 megacandelas. That's why it's being visible for up to 63 km around.
It's a very important lighthouse helping to conduct the traffic around dangerous waters where 2 oceans meet.
It is the branch of science, in which we study different phenomena of atmosphere including climate and weather.
Answer:
8.854 pF
Explanation:
side of plate = 0.1 m ,
d = 1 cm = 0.01 m,
V = 5 kV = 5000 V
V' = 1 kV = 1000 V
Let K be the dielectric constant.
So, V' = V / K
K = V / V' = 5000 / 1000 = 5
C = ε0 A / d = 8.854 x 10^-12 x 0.1 x 0.1 / 0.01 = 8.854 x 10^-12 F
C = 8.854 pF
<h2>
Answer: 7020.117 m/s</h2>
Explanation:
The velocity of a satellite describing a circular orbit is<u> constant</u> and defined by the following expression:
(1)
Where:
is the gravity constant
the mass of the massive body around which the satellite is orbiting, in this case, the Earth
.
the radius of the orbit (measured from the center of the planet to the satellite).
This means the radius of the orbit is equal to <u>the sum</u> of the average radius of the Earth
and the altitude of the satellite above the Earth's surface
.
Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. It depends on the mass of the massive body (the Earth).
Now, rewriting equation (1) with the known values: