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MArishka [77]
2 years ago
7

How can you determine an object's average velocity from a position time graph

Physics
1 answer:
viktelen [127]2 years ago
4 0

The average velocity can be calculated from the slope of the graph

Explanation:

In a position-time graph, the position is represented on the y-axis while the time is represented on the x-axis.

The slope of the graph is given by:

m=\frac{\Delta y}{\Delta x}

where

\Delta y is the change in the y-variable

\Delta x is the change in the x-variable

However, we have:

  • \Delta y corresponds to the change in position, therefore it is the displacement
  • \Delta x corresponds to the change in time

This means that the slope can be rewritten as

m=\frac{displacement}{time}

However, this ratio corresponds to the definition of average velocity:

velocity = \frac{displacement}{time}

Therefore, the slope of a position-time graph gives the average velocity.

Learn more about velocity:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

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There is still air inside of a house, which is pushing the roof upwards, so the forces are equal and the roof is not crushed.
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A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark
Natali5045456 [20]

The total displacement of the toy car at the given positions is 0.

The given parameters;

  • <em>First displacement of the car, = 5 cm left</em>
  • <em>Second displacement of the car, = 8 cm right</em>
  • <em>Third displacement of the car, = 3 cm to the left</em>

The total displacement of the car is calculated as follows;

  • <em>Let the </em><em>left </em><em>direction be "</em><em>negative </em><em>direction"</em>
  • <em>Let the </em><em>right </em><em>direction be "</em><em>positive </em><em>direction"</em>

\Delta x = - \ 5\ cm  \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0

Thus, the total displacement of the toy car at the given positions is 0.

Learn more about displacement here: brainly.com/question/18158577

6 0
2 years ago
Read 2 more answers
A certain 60.0 Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 11.6 kV/m.
yuradex [85]

Explanation:

Given that,

Frequency of the power line, f = 6 Hz

Value of maximum electric field strength of 11.6 kV/m

(a) The wavelength of this very low frequency electromagnetic wave is given by using relation as :

c=f\lambda

\lambda=\dfrac{c}{f}

\lambda=\dfrac{3\times 10^8\ m/s}{60\ Hz}

\lambda=5\times 10^6\ m

(b) As its can be seen that the wavelength of this wave is very high. It shows that it is a radio wave.

(c) The relation between the maximum magnetic field strength and maximum electric field strength is given by :

B_0=\dfrac{E_0}{c}\\\\B_0=\dfrac{11.6\times 10^3}{3\times 10^8}\\\\B_0=3.86\times 10^{-5}\ T

So, the maximum magnetic field strength is 3.86\times 10^{-5}\ T.

7 0
3 years ago
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A car moving has a speed of 35 m/s. What acceleration would it have if it took 5.0 s to come to a complete stop?
Pepsi [2]

Answer:

7

Explanation:

7 0
3 years ago
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For the airfoil and conditions in Problem 2.2, calculate the lift-to-drag ratio. Comment on its magnitude.
raketka [301]

Answer:

L/D= 112

Explanation:

Aerodynamics can be defined as the branch of dynamics which deals with the motion of air, their properties and the interaction between the air and solid bodies.

Aerodynamics law explains how an airplane is able to fly. There are four forces of flight, and they are; lift, weight, thrust and drag. The amount of lift generated by a wing divided by the aerodynamic drag is known as the lift to drag ratio.

Lift increases proportionally to the square of the speed.

The solutions to the question is the file attached to this explanation.

Lift,L= qC(l). S---------------------------(1).

and,

Drag,D = qC(d).S ----------------------(2).

Hence, Lift to drag ratio,L/D= C(l)/C(d).

Therefore, we have to compute various angle of attack.(check attached file)...

Then, (L/D) will then be equal to 112.

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