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3 years ago

How can you determine an object's average velocity from a position time graph

Physics

1 answer:

viktelen [127]3 years ago

4 0

The average velocity can be calculated from the slope of the graph

Explanation:

In a position-time graph, the position is represented on the y-axis while the time is represented on the x-axis.

The slope of the graph is given by:

$m=\frac{\Delta y}{\Delta x}$

where

$\Delta y$ is the change in the y-variable

$\Delta x$ is the change in the x-variable

However, we have:

$\Delta y$ corresponds to the change in position, therefore it is the displacement
$\Delta x$ corresponds to the change in time

This means that the slope can be rewritten as

$m=\frac{displacement}{time}$

However, this ratio corresponds to the definition of average velocity:

$velocity = \frac{displacement}{time}$

Therefore, the slope of a position-time graph gives the average velocity.

Learn more about velocity:

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Answer:

A. wavelength

Explanation:

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The propeller of a World War II fighter plane is 2.30 m in diameter. (a) What is its angular velocity in radians per second if i

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Answer with Explanation:

We are given that

Diameter of fighter plane=2.3 m

Radius= $r=\frac{d}{2}=\frac{2.3}{2}=1.15 m$

a.We have to find the angular velocity in radians per second if it spins=1200 rev/min

Frequency= $\frac{1200}{60}=20 Hz$

1 minute=60 seconds

Angular velocity= $\omega=2\pi f$

Angular velocity= $2\times \frac{22}{7}\times 20=125.7 rad/s$

b.We have to find the linear speed of its tip at this angular velocity if the plane is stationary on the tarmac.

$v=r\omega=1.15\times 125.7=144.56 m/s$

c.Centripetal acceleration= $\omega^2 r=(125.7)^2(1.15)=18170.56 m/s^2$

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3 years ago

A high-jumper, having just cleared the bar, lands on an air mattress and comes to rest. Had she landed directly on the hard grou

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Answer:

e. the air mattress exerts the same impulse, but a smaller net avg force, on the high-jumper than hard-ground.

Explanation:

This is according to the Newton's second law and energy conservation that the force exerted by the hard-ground is more than the force exerted by the mattress.

The hard ground stops the moving mass by its sudden reaction in the opposite direction of impact force whereas the mattress takes a longer time to stop the motion of same mass in a longer time leading to lesser average reaction force.

Mathematical expression for the Newton's second law of motion is given as:

$F=\frac{dp}{dt}$ ............................................(1)