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Arturiano [62]
3 years ago
10

When is the particle in figure (a) speeding up? (enter your answer using interval notation.)

Physics
1 answer:
worty [1.4K]3 years ago
4 0

Answer:

When your mom walks in the room, lol. I don't see a "figure A"

:D

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You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.80 mA when a sin
Anika [276]

Answer:

2.36 x 10^6 Hz

Explanation:

We know ;,

Iamp = 1.8mA

L = 0.45mH

VL = 12V

VL = IwL

VL = I x 2π x f x L

f = VL / (I x 2π x L)

f = 12 V/ (1.8mA x 2π x 0.45mH)

f = 12/(1.8x10^-3 x 2π x 0.45 x 10^-3)

f = 2.36 x 10^6 Hz

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4 years ago
A small rock is thrown straight up with initial speed V0 from
bagirrra123 [75]

Answer:

12 feet

Explanation:

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3 years ago
The vibrations along a transverse wave move in a direction _________.
GrogVix [38]

Answer: perpendicular to it oscillations.

Explanation: A transverse wave is a wave whose oscillations is perpendicular to the direction of the wave.

By perpendicular, we mean that the wave is oscillating on the vertical axis (y) of a Cartesian plane and the vibration is along the horizontal axis (x) of the plane.

Examples of transverse waves includes wave in a string, water wave and light.

Let us take a wave in a string for example, you tie one end of a string to a fixed point and the other end is free with you holding it.

If you move the rope vertically ( that's up and down) you will notice a kind of wave traveling away from you ( horizontally) to the fixed point.

Since the oscillations is perpendicular to the direction of wave, it is a transverse wave

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3 years ago
Naphthalene combustion can be used to calibrate the heat capacity of a bomb calorimeter. the heat of combustion of naphthalene i
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4 years ago
Dan is gliding on his skateboard at 4.0 m/s. He suddenly jumps backward off the skateboard, kicking the skateboard forward at 8.
Marta_Voda [28]

Answer:

3.6 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before jump = Total momentum after jump

<em>Note: Before Dan jump off the skateboard, they where both moving with the same velocity</em>

u(m+m') = mv+m'v'................. Equation 1

Where m = Dan's mass, m' = mass of the skateboard, u = common velocity before the jump, v = Dan's final velocity, v' = The final velocity of the skateboard.

make v the subject of the equation

v = [u(m+m')-m'v')]/m.............. Equation 2

Given: u = 4.0 m/s, m = 50 kg, m' = 5 kg, v' = 8 m/s

Substitute into equation 2

v = [4(50+5)-(5×8)]/50

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v = 180/50

v = 3.6 m/s

5 0
3 years ago
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