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Arturiano [62]
3 years ago
10

When is the particle in figure (a) speeding up? (enter your answer using interval notation.)

Physics
1 answer:
worty [1.4K]3 years ago
4 0

Answer:

When your mom walks in the room, lol. I don't see a "figure A"

:D

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The distance from earth to mars ranges between 780,000,000 km and 380,000,000 km depending on the time of the year. The speed of
ivann1987 [24]

Answer:

The minimum time, t = 21.11 m

Explanation:

Given,

The maximum distance between the Earth and Mars, d = 780,000,000 km

The maximum distance between the Earth and Mars, d = 780,000,000 km

The speed of the light, c = 300,000 km/s

The distance and speed of the object is related using the formula,

                           v = d / t

                            t = d / v

The minimum time it takes for data transmission is when the distance between the Mars and the Earth is at minimum.

Therefore,

                            t = 380,000,000 km / 300,000 km/s

                              = 1266.67 s

                              = 21.11 minutes

Hence, the minimum time it takes for data transmitted by the Mars Surveyor to reach earth, t = 21.11 minutes

6 0
3 years ago
MIDDLE SCHOOL SCIENCE<br> yee yee please answer 6, 7, and 8
Nikolay [14]

Answer:

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Explanation:

5 0
3 years ago
A train travels 92 miles in 11 1/2 hours. what is its average speed in miles per hour?
Gnom [1K]
The answer is 8 mph.
5 0
3 years ago
The capacitor can withstand a peak voltage of 590 volts. If the voltage source operates at the resonance frequency, what maximum
kirill115 [55]

Answer:

The maximum voltage is 41.92 V.

Explanation:

Given that,

Peak voltage = 590 volts

Suppose in an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is 1.20×10^{-2}\ \mu F.

We need to calculate the resonance frequency

Using formula of frequency

f=\dfrac{1}{2\pi\sqrt{LC}}

Put the value into the formula

f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}

f=2356.88\ Hz

We need to calculate the maximum current

Using formula of current

I=\dfrac{V_{c}}{X_{c}}

I=2\pi\times f\times C\times V_{c}

I=2\pi\times2356.88\times1.20\times10^{-8}\times590

I=0.1048\ A

Impedance of the circuit is

z=\sqrt{R^2+(X_{L}^2-X_{C}^2)}

At resonance frequency X_{L}=X_{C}

Z=R

We need to calculate the maximum voltage

Using ohm's law

V=I\times R

V=0.1048\times400

V=41.92\ V

Hence, The maximum voltage is 41.92 V.

4 0
3 years ago
The colour of star depend on its temperature, why?​
taurus [48]

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4 0
3 years ago
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