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4 years ago

The symbol, "I" represents- a. voltage b. power c. current d. resistance

Physics

1 answer:

Tanya [424]4 years ago

5 0

Answer:

The answer is C.

Explanation:

Current can be represented in the symbol of I.

The symbol for voltage is V.

The symbol for power is W.

The symbol for resistance is R.

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Without using afood flask, suggest another ways would you keep food warm a till to the hospital

AveGali [126]

Another way to keep food warm till you arrive at the hospital is by putting the food in a foil and wrapping it up with a towel to retain the heat.

<h3>What is Food preservation?</h3>

Food preservation is defined as the process by which a cooked food or process food is kept in such a way that microorganisms cannot affect their taste and texture.

To prevent a cooked food from getting cold, you can put the food in an aluminium foil and wrap it with a towel to prevent heat loss.

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8 0

2 years ago

During a test, a NATO surveillance radar system, operating at 12 GHz at 190 kW of power, attempts to detect an incoming stealth

ollegr [7]

Answer:

$4.72491\ \mu W/m^2$

$2\times 10^{-3}\ mW$

$6.10993\times 10^{-13}\ W/m^2$

$2.1454\times 10^{-5}\ N/C$

$7.15133\times 10^{-14}\ T$

Explanation:

A = Area of hemispher = $2\pi r^2$

r = Distance

P = Power

I = Intensity

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

c = Speed of light = $3\times 10^8\ m/s$

Intensity is given by

$I=\frac{P}{A}\\\Rightarrow I=\frac{190\times 10^3}{2\pi 80000^2}\\\Rightarrow I=4.72491\times 10^{-6}\ W/m^2=4.72491\ \mu W/m^2$

The intensity is $4.72491\ \mu W/m^2$

Power is given by

$P=IA\\\Rightarrow P=4.72491\times 10^{-6}\times 0.52\\\Rightarrow P=2.45695\times 10^{-6}=2\times 10^{-3}\ mW$

The power is $2\times 10^{-3}\ mW$

$I=\frac{P}{A}\\\Rightarrow I=\frac{2.45695\times 10^{-6}}{2\pi 80000^2}\\\Rightarrow I=6.10993\times 10^{-13}\ W/m^2$

The intensity is $6.10993\times 10^{-13}\ W/m^2$

Maximum electric field is given by

$E_0=\sqrt{\frac{2I}{c\epsilon_0}}\\\Rightarrow E_0=\sqrt{\frac{2\times 6.10993\times 10^{-13}}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E_0=2.1454\times 10^{-5}\ N/C$

Maximum value of electric field is $2.1454\times 10^{-5}\ N/C$

Magnetic field is given by

$B=\frac{E_0}{c}\\\Rightarrow B=\frac{2.1454\times 10^{-5}}{3\times 10^8}\\\Rightarrow B=7.15133\times 10^{-14}\ T$

The rms value of magnetic field is $7.15133\times 10^{-14}\ T$

5 0

4 years ago

What is parabolic motion?

Cerrena [4.2K]

Answer:

Pro jectile motion, also known as parabolic motion, consists in launching a body with a velocity that form an angle α with the horizontal

Explanation:

~♥~

8 0

2 years ago

A heat engine with 0.500 mol of a monatomic ideal gas initially fills a 1000 cm3 cylinder at 700 K . The gas goes through the fo

Zarrin [17]

Answer:

2234.63

Explanation:

Work done per cycle by the engine is calculated as;

$W=\int p \ dv$

#Since volume doesn't change in the isochoric steps, there is no work done, hence:

$W_2=W_3=0$

#For an isothermal change of state(ideal gas):

$pV=nRT\\\\W=P_iV_ i\int \frac{1}{V} \ dV\\\\=P_iV_ iIn(V_f/V_i)$

#for the expansion process:

$W_i=0.5mol\times8.3145J/molK\times 700K \ In(6000cm^3/1000cm^3)\\\\W_i=5214.15J$

$W_4=0.5mol\times8.3145J/molK\times 400K \ In(6000cm^3/1000cm^3)\\\\W_4=-2979.52$

$W=W_1+W_2+W_3+W_4\\\\=5214.15J-2979.52\\\\=2234.63J$

Hence, the engine does 2234.63J per second.

8 0

4 years ago

A small sphere with mass 5.00×10−7 kg and charge +8.00 μC is released from rest a distance of 0.500 m above a large horizontal i

Damm [24]

<span>Work done on charge is W = Eqd = σ/(2ε₀) x q x d = {(8.00 x 10⁻¹²)/(2 x 8.854187 x 10⁻¹²)} x 3.00 x 10⁻⁶ x (0.650 - 0.250) = 5.42116402J. KE of sphere = 0.5mv² = 0.5 x 5.00 x 10⁻⁷v² = work done by E-field on charge during its fall = 5.42116402→ v = 4657 m/s.</span>

6 0

3 years ago