Answer:
h = 2.64 meters
Explanation:
It is given that,
Mass of one ball, 
Speed of the first ball,
(upward)
Mass of the other ball, 
Speed of the other ball,
(downward)
We know that in an inelastic collision, after the collision, both objects move with one common speed. Let it is given by V. Using the conservation of momentum to find it as :


V = 7.2 m/s
Let h is the height reached by the combined balls of putty rise above the collision point. Using the conservation of energy as :



h = 2.64 meters
So, the height reached by the combined mass is 2.64 meters. Hence, this is the required solution.
Answer:
a) Θ = ω₀*t + ½αt² To complete first revolution 2π rads = 0*t + ½αt² and to complete the first and second combined 4π rads = 0*t + ½α(t+0.810s)² Divide second by first: 2 = (t + 0.810s)² / t² This is quadratic in t and has roots at t = -0.336 s ← ignore and t = 1.96 s ◄ b) Use either equation from above: 2π rads = 0*t + ½α(1.96s)² α = 3.27 rad/s² ◄ Hope this helps!
Explanation:
Answer:
0.0018 W/m²
Explanation:
Power and intensity are related as:

P= 20.0 W (given)
r = 30.0 m (given)

Intensity in decibels:

Answer:
The final speed is 9.89 m/s.
Explanation:
Initial speed of skydiver is 0 as it was rest.
Acceleration of the skydiver is 9.8 m/s²
It accelerates for the first 5 m of their fall.
It is required to find their final speed. Let v is the final speed. It can be calculated using third equation of motion.

Here, u = 0
a = 9.8 m/s²
s = 5 m

So, the final speed is 9.89 m/s.