Answer:
pH=3.38
Explanation:
We are given the concentrations of the weak acid and its conjugate base so we need to use the henderson hasslebalch equation
pH=pKa + log (concentration A-/concentration of HA)
A- : conjugate base NaC3H5O3
HA: weak acid HC3H5O3
so if we plug in what we are given
pH= 3.08 + log (1M/.5M)
pH= 3.38
Explanation:
Neutralization reaction is a type of chemical reaction in which an acid and a base react together to form a salt <u><em>and water</em> </u>as products.
Answer:
2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2
Explanation:
2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2
As hot as my cooter lips
hope this helped :)
Answer:
b 1 mole of nitrogen 6 hydro 1 sulfur