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PtichkaEL [24]
3 years ago
5

An object is launched at 9.8 meters per second (m/s) from a 308.7-meter tall platform. The function that represents the object's

height s at time t seconds after launch is
s(t) = −4.9t2 + 9.8t + 308.7,
where s is in meters. When does the object strike the ground?
Mathematics
1 answer:
Sedaia [141]3 years ago
8 0

this is the full answer for you're Q

please give me good

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Help help help please
yaroslaw [1]

Answer:

∠TUY = 120°

Step-by-step explanation:

There are two rules you can apply here:

1) The sum of the angles inside a triangle is 180°.  This means that ∠SUT = 180° - 70° - 50 ° = 60°

2) A vector coming out of a line two angles between itself and the line, and they add up to 180° as well. This means that ∠TUY = 180° - ∠SUT.  So ∠TUY = 180° - 60° = 120°

So the missing angle one hundred and twenty degrees.

4 0
3 years ago
Can someone pls help me?
nignag [31]

Step-by-step explanation:

ofc , so that is that and the other is that

4 0
3 years ago
Find the rang of the data 81 78 74 88 73 76 93 98 78 80
Makovka662 [10]
Range = highest number - smallest number
= 98- 73
= 25
8 0
4 years ago
Porfavor alguien me dice cuanto es esto 3×?=20​
stiv31 [10]

Answer:

6.66666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666

Step-by-step explanation:

Que no se te olvide el punto

6 0
3 years ago
Read 2 more answers
On a very cold morning, it was -8°F. As the day went on the temperature rose 2
ipn [44]

Answer:

y=2x-8

Step-by-step explanation:

Fill the numbers of hours passed into z

E.g If 5 hours have passed

2(5)-8

10-8

=2

5 0
3 years ago
Read 2 more answers
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