The Agricultural Extension Agent's Office has tracked fertilizer application and crop yields for a variety of chickpea and has r
1 answer:
Answer:
Following are the solution to the given points:
Explanation:
In point 1:
The yield added by the regression equation increases 8.5 times of per each unit of fertilizer.
In point 2:
Definition i.e. describes the percentage of variation. Consequently, the value of Fertilizer variable describes 0.79 percent throughout the variance of the Bushels variable.
In point 3:
At , Bushels has an fertilizer of 60.
In point 4:
The fertilizer should be 100 when bushels are:
In point 5:
Increased that amount of fertilizer will reduce the amount of bushels unless the value of determination was negative.
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Answer: The answer is C
Explanation: I got this correct on a test
Answer:
The correct answer is D.
Explanation:
Equity = $231,000
No. of outstanding shares = 5,000
Price of share =
Price of share = $46.2
Repurchased shares worth $18,000
No. of shares repurchased =
No. of shares repurchased = 390
When the shares would have been repurchased then the value of equity would decrease by the same amount.
Revised equity = $231,000 - $18,000
Revised equity = $213,000
No. of shares outstanding = 5,000 - 390
No. of shares outstanding = 4,610
Thus, the price of each share would be:
Share price =
Share price = $42.60
Answer:
1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.
2) We need to satisfy the following inequalities:
So then we satisfy this condition
3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.
So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:
So then the answer for this case would be:
a. Yes.
Explanation:
For this case we assume that the question is: If in the experiment described we can use the normal approximation for the proportion of interest.
For this case we have a sample of n =25
And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.
X = 13 represent the number of students in the sample selected that have a time more than 20 min.
And then the estimated proportion of interest would be:
And we want to check if we can use the normal approximation given by:
So in order to do this approximation we need to satisfy some conditions listed below:
1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.
2) We need to satisfy the following inequalities:
So then we satisfy this condition:
3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.
So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:
So then the answer for this case would be:
a. Yes.