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Alex17521 [72]
3 years ago
11

What’s the meaning of physics??

Physics
1 answer:
lukranit [14]3 years ago
7 0

Answer:the branch of science concerned with the nature and properties of matter and energy. The subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.

Explanation:

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The current through inductance L is given by I=I0e−t/τ
ohaa [14]
ΔVl = L di/dt
i = i₀e -t/T
di/dt = i₀ × (-1/T) e -t/T
ΔVl = L× (-I/T i₀e -t/T
ΔVl = -L/T i₀e -t/T

b. 15mm, i₀ = 36mA, T = 1.1m
t= Os
ΔVl = 0,491V
C. t = 1ms
ΔVl = 0.198V
t = 2ms
ΔVl = 0.08V

E. t = ms
ΔVl = 0.032V
6 0
4 years ago
What is a moon node?<br><br><br><br><br><br><br><br>have a great day ​
RideAnS [48]

Answer:

lunar node in other words is either of the two orbital nodes of the Moon, that is, the two points at which the orbit of the Moon intersects the ecliptic. The ascending node is where the Moon moves into the northern ecliptic hemisphere, while the descending node is where the Moon enters the southern ecliptic hemisphere

3 0
3 years ago
Read 2 more answers
A large ball of Play-Doh with a mass of 0.04kg is launched from a catapult with an initial
ryzh [129]

Answer:

  ≈ 6.68 m/s

Explanation:

A suitable formula is ...

  vf^2 -vi^2 = 2ad

where vi and vf are the initial and final velocities, a is the acceleration, and d is the distance covered.

We note that if the initial launch direction is upward, the velocity of the ball when it comes back to its initial position is the same speed, but in the downward direction. Hence the problem is no different than if the ball were initially launched downward.

Then ...

  vf = √(2ad +vi^2) = √(2·9.8 m/s^2·1.0 m+(5 m/s)^2) = √44.6 m/s

  vf ≈ 6.68 m/s

The ball hits the ground with a speed of about 6.68 meters per second.

__

We assume the launch direction is either up or down.

3 0
3 years ago
Edwin Hubble categorized galaxies according to their
Llana [10]
     Your answer would be that Hubble categorized galaxies by their shape.
6 0
4 years ago
A 400 kg object is sitting at rest at the top of a hill that is 30.0m high and 80.0m long measured along the hill . If there is
olchik [2.2K]
Theater=sin^-1(30/80)
theater=22
F=400gsin22=150N
F=ma
150=400a
a=0.375ms^-2
v^2-u^2=2as
v^2-0=2x0.375x80
v=7.75ms^-1
3 0
4 years ago
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