The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².
<h3>What will be the maximum acceleration of the truck to avoid tipping over?</h3>
The maximum acceleration is obtained by taking clockwise moments about the tipping point of rotation.
Clockwise moment = Anticlockwise moment
Ft * 1.58 m = F * 0.67 m
where
- Ft is tipping force = mass * acceleration, a
- F is weight = mass * acceleration due to gravity, g
m * a * 1.58 = m * 9.81 * 0.67
a = 4.15 m/s²
The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².
In conclusion, the acceleration of the truck is found by taking moments about the tipping point.
Learn more about moments of forces at: brainly.com/question/27282169
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Answer:
625000 N/ m
Explanation:
m= 20 kg
v= 30 m/s
x= 12 cm
k = ?
Here when the mass when hits at spring its speed is
Vi= 30 m/s
Finally it comes to rest after compressing for 12 cm
i-e Vf = 0 m/s
Distance= S= 12 cm = 0.12 m
using
2aS= Vf2 - Vi2
==> 2a ×0.12 = o- 30 × 30
==> a = 900 ÷ 0.24 = 3750 m/sec2
Now we know;
F = ma
F= -Kx
==> ma= -kx
==> 20 × 3750 = -K × 0.12
==> k = 625000 N/ m
You can calculate potential energy by:
U = m.g.h
Where, U = potential energy
m = mass
g = acceleration due to gravity
h = height
Hope this helps!
Answer:
m = 5.22 kg
Explanation:
The force acting on the bucket is 52.2 N.
We need to find the mass of the bucket.
The force acting on the bucket is given by :
F = mg
g is acceleration due to gravity
m is mass
So, the mass of the bucket is 5.22 kg.
