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MakcuM [25]
2 years ago
9

25. In the formula for a molecular compound, which atom generally comes first? You may went

Chemistry
1 answer:
vovikov84 [41]2 years ago
3 0

Answer:

For organic compounds, carbon and hydrogen are listed as the first elements in the molecular formula, and they are followed by the remaining elements in alphabetical order. For example, for butane, the molecular formula is C 4 H 10.

Explanation:

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X2o3 express you answer as a whole number
kobusy [5.1K]
 <span>2.40 - 1.68 =0.72 g of oxigen 
moles = 0.72/16 g/mol=0.045 

moles x = 1.68/ 55.9=0.03 

0.03/0.03 = 1 = x 
0.045 / 0.03 = 1.5 = O 

to get whole numbers multiply by 2 

x2O3 

X2O3 +3 CO = 2 X + 3 CO2</span>
4 0
3 years ago
The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224
Margarita [4]

Explanation:

the answer and explanation is in the picture

hope this helps

please like and Mark as brainliest

8 0
3 years ago
Which of the following gases is not an important component of soil?
Scilla [17]

Sorry my friend you don't have options so It can't be answered...

6 0
3 years ago
In the reaction: CH3COO-+NH4+----------CH3COOH+NH3 what is the reactant acid and its conjugate base?
WINSTONCH [101]

Answer : The reactant acid and conjugate base in this reaction is, NH_4^ and NH_3.

Explanation :

Conjugate acid : A species that is formed by receiving of a proton (H^+) by a base is known as conjugate acid.

Conjugate base : A species that is formed by donating of a proton by an acid is known as conjugate base.

The given chemical reaction is,

CH_3COO^-+NH_4^+\rightleftharpoons CH_3COOH+NH_3

In this reaction, CH_3COO^-(base) react with NH_4^(acid) to give CH_3COOH(conjugate acid) and NH_3(conjugate base).

Therefore, the reactant acid and conjugate base in this reaction is, NH_4^ and NH_3.

8 0
3 years ago
One brand of laundry bleach is an aqueous solution containing 4.00% sodium hypochlorite (naocl) by mass. you may want to referen
Vlad1618 [11]
Answer is: <span>molarity of this solution is 0,55 mol/l.
</span>If we use 100 ml of solution:
V(solution) = 100 ml ÷ 1000 ml/l = 0,1 l.
ω(NaClO) = 4,00% = 0,04.
d(solution) = 1,02 g/ml.
m(solution) = V(solution) · d(solution).
m(solution) = 100 ml · 1,02 g/ml.
m(solution) = 102 g.
m(NaClO) = ω(NaClO) · m(solution).
m(NaClO) = 0,04 · 102 g = 4,08 g.
n(NaClO) = m(NaClO) ÷ M(NaClO).
n(NaClO) = 4,08 g ÷ 74,44 g/mol = 0,055 mol.
c(NaClO) = 0,055 mol ÷ 0,1 l = 0,55 mol/l.
3 0
3 years ago
Read 2 more answers
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