When we describe the energy of a particle as quantized, we mean that only certain values of energy are allowed. ... In this case, whenever we measure the particle's energy, we will find one of those values. If the particle is measured to have 4 Joules of energy, we also know how much energy the particle can gain or lose. Quantized energy means that the electrons can possess only certain discrete energy values; values between those quantized values are not permitted
Hi there!
p = e-3
s = f-1
f = i-7
d = g-5
Hope that helps!
Brady
<u>Given:</u>
Change in internal energy = ΔU = -5084.1 kJ
Change in enthalpy = ΔH = -5074.3 kJ
<u>To determine:</u>
The work done, W
<u>Explanation:</u>
Based on the first law of thermodynamics,
ΔH = ΔU + PΔV
the work done by a gas is given as:
W = -PΔV
Therefore:
ΔH = ΔU - W
W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ
Ans: Work done is -9.8 kJ
Ok we can use boyle’s law (stating that P is proportional to V) to make the equation (P1V1) =(P2V2).
once we’ve done this, we can plug in the numbers:
(800•500) = (200•V2)
and then we get that
V2= 2000 ml
hope this helps!! :)
BAS might be an improperly capitalized: BAs, BaS
PTF2 might be an improperly capitalized: PtF2
BAF2 might be an improperly capitalized: BaF2
PTS might be an improperly capitalized: PtS
