Answer:
pH = 1.32
Explanation:
H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺
This problem involves a weak diprotic acid which we can solve by realizing they amount to buffer solutions. In the first deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:
So first calculate the moles reacted and produced:
n H₂M = 0.864 g/mol x 1 mol/ 116.072 g = 0.074 mol H₂M
54 mL x 1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH
it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.
moles H₂M left = 0.074 - 0.015 = 0.059
moles HM⁻ produced = 0.015
Using the Henderson - Hasselbach equation to solve for pH:
ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325
Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.
For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.
Answer:
Ke = mgv
Explanation:
(60)(9.81)(2) =1177.2 joules persecond or Watts.
1.177 kilowatts
Answer: If homeostasis is disrupted, it must be controlled or a disease/disorder may result.
Explanation: What happens if there's disruption? Your body systems work together to maintain balance. If that balance is shifted or disrupted and homeostasis is not maintained, the results may not allow normal functioning of the organism.
Well i did some research and i found out now im not sure if this is completely true but supposedly tachyons are even faster than the speed of light
<u>Answer:</u>
<em>4.5 L water we have in litres (L).</em>
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<u>Explanation:</u>
where
= Final T - Initial T
Q is the heat energy in calories
c is the specific heat capacity (for water 1.0 cal/(g℃))
m is the mass of water
Plugging in the values
So,
Volume of water = mass/density
=4.5 L (Answer)
