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viva [34]
3 years ago
9

The lab procedure you just studied involves

Chemistry
1 answer:
Svetllana [295]3 years ago
8 0

Answer: c , v, c, c, v

Explanation:

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in an experiment 3.5g of element A reacted with 4.0g of element G to form a compound Calculate the empirical formula for this co
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Additional information

Relative atomic mass(Ar) : A=7, G=16

The empirical formula : A₂G

<h3>Further explanation</h3>

Given

3.5g of element A

4.0g of element G

Required

the empirical formula for this compound

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.

The empirical formula also shows the simplest mole ratio of the constituent elements of the compound

mol of element A :

\tt mol=\dfrac{mass}{Ar}\\\\mol=\dfrac{3.5}{7}=0.5

mol of element G :

\tt mol=\dfrac{4}{16}=0.25

mol ratio A : G = 0.5 : 0.25 = 2 : 1

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A and B are two imaginary substances. The molecules of substance A have weak electrical forces between them. The
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Name the element which lies in group IA and 3rd period. What is the valency of it and why?​
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