Based on experiment 1:
Mass of Hg = 1.00 g
Mass of sulfide = 1.16 g
Mass of sulfur = 1.16 - 1.00 = 0.16 g
# moles of Hg = 1 g/200 gmol-1 = 0.005 moles
# moles of S = 0.16/32 gmol-1 = 0.005 moles
The Hg:S ratio is 1:1, hence the sulfide is HgS
Based on experiment 2:
Mass of Hg taken = 1.56 g
# moles of Hg = 1.56/200 = 0.0078
Mass of S taken = 1.02 g
# moles of S = 1.02/32 = 0.0319
Hence the limiting reagent is Hg
# moles of Hg reacted = # moles of HgS formed = 0.0078 moles
Molar mass of HgS = 232 g/mol
Therefore, mass of HgS formed = 0.0078 * 232 = 1.809 g = 1.81 g
<u>Answer:</u> The partial pressure of carbon dioxide at equilibrium is 0.0056 atm
<u>Explanation:</u>
The given chemical equation follows:

<u>Initial:</u> 4.00
<u>At eqllm:</u> 4.00-2x x x
The expression of
for above reaction follows:

The partial pressure of pure solids and liquids are taken as 1 in the equilibrium constant expression.
We are given:

Putting values in above expression, we get:

Neglecting the value of x = 718.28 because equilibrium pressure cannot be greater than initial pressure
Partial pressure of
= 0.0056 atm
Hence, the partial pressure of carbon dioxide at equilibrium is 0.0056 atm
<span>The answer is 1. Carbon dioxide has two covalent bonds amid every oxygen atom and the carbon atom. When molecules are balanced, though, the atoms pull similarly on the electrons and the control distribution is uniform. Symmetrical molecules are therefore nonpolar.</span>
Answer:
r² x h
Explanation:
A can is cylindrical in nature. Using the formula of the volume of the can, we can find this unknown volume.
The volume of cylinder is given as:
Volume of a cylinder = Area x height
Volume of a cylinder =
r² x h
Therefore density of the can;
Density = 
Answer:
Explanation:
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