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3 years ago

A car accelerates on a horizontal road due to the force exerted by :

1 answer:

8 0

I am absolutely sure that if a car accelerates on a horizontal road due to the force exerted by road. I consider the last option from the list represented above to be the correct one because the road oses as a nice example of a frictional force. Hope you will agree with me and find it helpful! Regards!

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A rope passes over a fixed sheave with both ends hanging straight down. The coefficient of friction between the rope and sheave

Oliga [24]

Answer:3.51

Explanation:

Given

Coefficient of Friction $\mu =0.4$

Consider a small element at an angle \theta having an angle of $d\theta$

Normal Force $=T\times \frac{d\theta }{2}+(T+dT)\cdot \frac{d\theta }{2}$

$N=T\cdot d\theta$

Friction $f=\mu \times Normal\ Reaction$

$f=\mu \cdot N$

and $T+dT-T=f=\mu Td\theta$

$dT=\mu Td\theta$

$\frac{dT}{T}=\mu d\theta$

$\int_{T_2}^{T_1}\frac{dT}{T}=\int_{0}^{\pi }\mu d\theta$

$\frac{T_2}{T_1}=e^{\mu \pi}$

$\frac{T_2}{T_1}=e^{0.4\times \pi }$

$\frac{T_2}{T_1}==e^{1.256}$

$\frac{T_2}{T_1}=3.51$

7 0

3 years ago

Calculate the work done to push a 200-N object 5-meters

AVprozaik [17]

1000 joules
jskskmxk dnd

6 0

2 years ago

A man pushes an 250-N crate at constant speed a distance of 30.0 m upward along a rough slope that makes an angle of 60° with th

mel-nik [20]

Answer:

6495.19 Joule

Explanation:

F = Weight of the crate = 250 N

d = Distance the cart is pushed = 30 m

θ = Angle of inclination = 60°

The weight of the crate will be resloved into two components

Fdsinθ and Fdcosθ

Work done by the force of gravity is

W = Fdsinθ

⇒W = 250×30×sin60

⇒W = 6495.19 Joule

∴ The work done by the force of gravity is 6495.19 Joule

8 0

3 years ago

An object is lifted from the surface of aspherical planet to an altitude equal to the radius of the planet.As a result, what hap

serg [7]

An object is lifted from the surface of a spherical planet to an altitude equal to the radius of the planet.

As a result, the object's mass remains the same, and its weight decreases to 1/4 of whatever it is when the object is on the planet's surface.

8 0

3 years ago

Amy has a mass of 30 kg, and she is riding a skateboard traveling 5 m/s. What is her momentum?

Flauer [41]

Hey there!

So we know that m*v=P.
And in this question m=30
v=5 m/s
P = 30*5 Kgm/s
P = 150 Kgm/s

So, your final answer is 150 Kg.m/s

Hope this helps! :)

5 0

3 years ago

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