Answer:
0.661 m/s²
Explanation:
g = MG / r²
g = (1.31×10²² kg) (6.67×10⁻¹¹ m³/kg/s²) / (1.15×10⁶ m)²
g = 6.61×10⁻¹ m/s²
g = 0.661 m/s²
 
        
             
        
        
        
Answer:
The electrical potential energy is 0.027 Joules.
Explanation: 
The values from the question are 
charge (q) = 
Electric Field strength (E) = 
Distance from source (d) = 0.030 m
Now the formula for the electrical potential energy (U) is given by 

So now insert the values to find the answer 

On further solving 

 
        
             
        
        
        
If all the energy she put into bending the bow is completely 
transmitted to the arrow, then the arrow has the 100 joules 
of kinetic energy when it leaves the bow.
                 Kinetic energy = (1/2) (mass) (speed)²
                         100 J        = (1/2) (0.5 kg) (speed²)
Divide each side by 0.25 kg:    100 J / 0.25 kg = speed²
 [ joule ] = [ newton-meter ] = kg-m²/sec²
                                                100 kg-m²/sec² / 0.25 kg = speed²
                                                 400 m²/sec² = speed²
Take the square root of each side:     speed = √400 m/s
                                                                                20 m/s 
                                                                    (about 44.7 mph)