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dezoksy [38]
3 years ago
15

A 95 kg clock initially at rest on a horizontal floor

Physics
1 answer:
Nataly [62]3 years ago
4 0

Answer:

You are given that the mass of the clock M is 95 kg.

This is true whether the clock is in motion or not.

Fs is the frictional force required to keep the clock from moving.

Thus Fk = uk W = uk M g      the force required to move clock at constant speed.     (the kinetic frictional force)

uk = 560 N / 931 N = .644   since the weight of the clock is 931 N  (95 * 9.8)

us  is the frictional force requited to start the clock moving

us = static frictional force = 650 / 931 -= .698

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Butoxors [25]

Answer:

Explanation:

Given

mass of bus along with travelers travelling in North direction is m_1=1.6\times 10^4 kg

speed of bus towards North v_1=15.2 km/h\approx 4.22\ m/s

mass of bus travelling in South direction is m_2=1.578\times 10^4 kg

speed of bus v_2=12.2 km/h\approx 3.38\ m/s

mass of each Passenger in south moving bus m_0=64.8 kg

Momentum of North moving bus

P_1=m_1\times v_1

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P_1=6.768\times 10^4 kg-m/s

Momentum with south moving bus

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For total momentum to be towards south

P_2-P_1 should be greater than 0

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n=\frac{4243.6686}{64.8}=65.48\approx 66    

5 0
3 years ago
A railroad track and a road cross at right angles. An observer stands on the road and watches an eastbound train traveling at 60
mamaluj [8]

Answer:

After 4 s of passing through the intersection, the train travels with 57.6 m/s

Solution:

As per the question:

Suppose the distance to the south of the crossing watching the east bound train be x = 70 m

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y(t) = 60t

Now,

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Since, the road cross at right angles, thus by Pythagoras theorem:

z(t) = \sqrt{x^{2} + y(t)^{2}}

z(t) = \sqrt{70^{2} + 60t^{2}}

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\frac{dz(t)}{dt} = \frac{1}{sqrt{3600t^{2} + 4900}}\times 3600t

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4 0
2 years ago
​A piston–cylinder assembly contains 5.0 kg of air, initially at 2.0 bar, 30 oC. The air undergoes a process to a state where th
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Answer:

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