1 year ago

Obtain the formula for the focal length of a lens in terms of object distance (u)

Physics

1 answer:

Alexxx [7]1 year ago

6 0

Answer:

m=image distance÷object distance

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How do you find the capacitance in this?

Lostsunrise [7]

Answer:

Explanation:

parallel capacitances add directly

Series capacitances add by reciprocal of sum of reciprocals.

Ceq = [ C ] + [1 / (1/C + 1/C)] + [1 / (1/C + 1/C + 1/C)]

Ceq = [ C ] + [C / 2] + [C / 3]

Ceq = [ 6C/6 ] + [3C / 6] + [2C / 6]

Ceq = 11C/6

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2 years ago

Determine the mechanical energy of this object a 1-kg ball rolls on the ground at <br> m/s

dedylja [7]

Mechanical energy = potential energy + kinetic energy
The ball is on the ground so it has no potential energy. that's all i know.

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3 years ago

If u drop a bar of soap on the floor then is the floor clean or is the bar of soap dirty? Lol I’m so bored i dont even know what

emmainna [20.7K]

Answer:

CLEAN

Explanation:

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3 years ago

Read 2 more answers

An object of length 3.00 cm is inside a plastic block with index of refraction 1.40. If the object is viewed from directly above

Lilit [14]

The length of its image = $-3cm$

Given,

length of object, $h_o = 3 cm$

We know, for flat refracting surface,

Image distance = object distance

So,

magnification is = $-1$

length of the image,

$h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm$

Here, negative sign means inverted image.

For more information on refraction, visit

brainly.com/question/14760207?referrer=searchResults

3 0

2 years ago

If 3.61 m3 of a gas initially at STP is placed under a pressure of 2.67 atm , the temperature of the gas rises to 37.9 ∘C. What

Pavel [41]

Answer: $1.54m^3$

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas at STP = 1 atm

$P_2$ = final pressure of gas = 2.67 atm

$V_1$ = initial volume of gas = $3.61m^3$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas at STP = $0^oC=273+0=273K$

$T_2$ = final temperature of gas = $37.9^oC=273+37.9=310.9K$

Now put all the given values in the above equation, we get:

$\frac{1atm\times 3.61m^3}{273K}=\frac{2.67\times V_2}{310.9K}$

$V_2=1.54m^3$

Thus the final volume will be $1.54m^3$

7 0

3 years ago