In what way are the electron configurations of h, li, na, k, rb, and cs similar?

Phosphoric acid, which is commonly used as rust inhibitor, food additive and etching agent for dental and orthopedic use, can be

Sphinxa [80]

Answer:

$P_4_{(I)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}$

Explanation:

The first step is:

$P_4_{(I)}+5O_2_{(g)}\rightarrow 2P_2O_5_{(g)}$

Second step is:

$P_2O_5_{(g)}+3H_2O_{(l)}\rightarrow 2H_3PO_4_{(l)}$

Multiplying second step by 2, and adding both the steps, we get that:

$P_4_{(I)}+5O_2_{(g)}+2P_2O_5_{(g)}+6H_2O_{(l)}\rightarrow 2P_2O_5_{(g)}+4H_3PO_4_{(l)}$

Cancelling common species, we get that:

$P_4_{(l)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}$

6 0

3 years ago

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4

Anna71 [15]

Answer:

31.652g of Na3PO4

Explanation:

We'll begin by calculating the molarity of Na3PO4 solution. This can be achieved as shown below:

Na3PO4 will dessicate in solution as follow:

Na3PO4(aq) —> 3Na+(aq) + PO4³¯(aq)

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of sodium ion, Na+.

Therefore, xM Na3PO4 will produce 1.10M sodium ion, Na+ i.e

xM Na3PO4 = (1.10 x 1)/3

xM Na3PO4 = 0.367M

Therefore, the molarity of Na3PO4 is 0.367M.

Next, we shall determine the number of mole of Na3PO4 in the solution. This is illustrated below:

Molarity of Na3PO4 = 0.367M

Volume = 525mL = 525/1000 = 0.525L

Mole of Na3PO4 =..?

Molarity = mole /Volume

0.367 = mole /0.525

Cross multiply

Mole of Na3PO4 = 0.367 x 0.525

Mole of Na3PO4 = 0.193 mole.

Finally, we shall convert 0.193 mole of Na3PO4 to grams. This is illustrated below:

Molar mass of Na3PO4 = (23x3) + 31 + (16x4) = 164g/mol

Mole of Na3PO4 = 0.193 mole

Mass of Na3PO4 =.?

Mass = mole x molar mass

Mass of Na3PO4 = 0.193 x 164

Mass of Na3PO4 = 31.652g

Therefore, 31.652g of Na3PO4 is needed to prepare the solution.

6 0

3 years ago

How any moles of H2O will be produced from 12.3 moles of HCL reacting with Ca(OH)2?

stiks02 [169]

Answer:

\large \boxed{\text{12.3 mol HCl}}

Explanation:

We need a balanced chemical equation with moles.

2HCl +Ca(OH)₂ ⟶ CaCl₂ + 2H₂O

n/mol: 12.3

The molar ratio is 2 mol H₂O:2 mol HCl.

$\text{Moles of H$_{2}$O} = \text{12.3 mol HCl} \times \dfrac{\text{2 mol H$_{2}$O}}{\text{2 mol HCl}} = \textbf{12.3 mol HCl}\\\\\text{The reaction produces $\large \boxed{\textbf{12.3 mol HCl}}$}$

3 0

3 years ago

A nuclear fission reaction has mass difference between the products and the reactants of 0.0284 amu. Calculate the

notsponge [240]

Answer:

C) 4.24 x $10^{-12}$

Explanation:

E = Δm $c^{2}$

Δm = 0.0284 x 1.66 x $10^{-27}$ kg = 4.714x $10^{-29}$ kg

putting value in above equation

E = 4.714x $10^{-29}$ kg x (3x $10^{8}$ $)^{2}$ = 4.24 x $10^{-12}$

6 0

3 years ago

This is 25 points. Pick any of the 6 questions and show how you did it. I just need to see how you do it and get the answer. You

FromTheMoon [43]

I choose question 1, so molarity is the concentration of a soulution expressed as the number of moles of solute by the litress of soulution. to get molarity you divide the moles of soulute by the litress of solution. soo 1 calculate the number of moles of solute present. 2 Calculate the number of litress solution present. 3. divide the number of moles of solute by the number of litress of solution
soo 1 mol of NaOH has a mass of 40.00 g, so moles of NaOH= 26.7. 1 mole divided 40.00 = 0.375. litress of solution = 650 g. im not sure why its a g i usally do it Ls so i guess its the way your teacher wants you to do it so do you know how to do that. so molarity = moles of solute and litress solution. sorry this probably didnt help i just wanted to add something that might help. im still working on this stuff myself hope this helps.

5 0

3 years ago