Question

A nuclear fission reaction has mass difference between the products and the reactants of 0.0284 amu. Calculate the

Answer 1

Answer:

C) 4.24 x $10^{-12}$

Explanation:

E = Δm$c^{2}$

Δm = 0.0284 x 1.66 x $10^{-27}$ kg = 4.714x$10^{-29}$kg

putting value in above equation

E = 4.714x$10^{-29}$kg x (3x$10^{8}$$)^{2}$ = 4.24 x $10^{-12}$