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Vedmedyk [2.9K]
2 years ago
13

A nuclear fission reaction has mass difference between the products and the reactants of 0.0284 amu. Calculate the

Chemistry
1 answer:
notsponge [240]2 years ago
6 0

Answer:

C) 4.24 x 10^{-12}

Explanation:

E = Δmc^{2}

Δm = 0.0284 x 1.66 x 10^{-27} kg = 4.714x10^{-29}kg

putting value in above equation

E = 4.714x10^{-29}kg x (3x10^{8})^{2} = 4.24 x 10^{-12}

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Answer: do

Explanation:

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What will lithium and bromine make when they bond
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If all other variables remain unchanged, what happens to the output force when the area of the input piston is doubled?
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Answer:

1250N

Explanation:

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So By Pascal's Law

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3 0
3 years ago
if i add 25 ml of water to 135 ml of a 0.25 M NaOH solution what will the molarity of the diluted solution be​
DENIUS [597]

Answer:

0.21 M. (2 sig. fig.)

Explanation:

The molarity of a solution is the number of moles of the solute in each liter of the solution. The unit for molarity is M. One M equals to one mole per liter.

How many moles of NaOH in the original solution?

n = c \cdot V,

where

  • n is the number of moles of the solute in the solution.
  • c is the concentration of the solution. c = 0.25 \;\text{M} = 0.25\;\text{mol}\cdot\textbf{L}^{-1} for the initial solution.
  • V is the volume of the solution. For the initial solution, V = 135\;\textbf{mL} = 0.135\;\textbf{L} for the initial solution.

n = c\cdot V = 0.25\;\text{mol}\cdot\textbf{L}^{-1} \times 0.135\;\textbf{L} = 0.03375\;\text{mol}.

What's the concentration of the diluted solution?

\displaystyle c = \frac{n}{V}.

  • n is the number of solute in the solution. Diluting the solution does not influence the value of n. n = 0.03375\;\text{mol} for the diluted solution.
  • Volume of the diluted solution: 25\;\text{mL} + 135\;\text{mL}  = 160\;\textbf{mL} = 0.160\;\textbf{L}.

Concentration of the diluted solution:

\displaystyle c = \frac{n}{V} = \frac{0.03375\;\text{mol}}{0.160\;\textbf{L}} = 0.021\;\text{mol}\cdot\textbf{L}^{-1} = 0.021\;\text{M}.

The least significant number in the question comes with 2 sig. fig. Keep more sig. fig. than that in calculations but round the final result to 2 sig. fig. Hence the result: 0.021 M.

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Colligative properties include lowering the freezing point, lowering the vapor pressure, and raising the boiling point.

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