The strong Base with a pH of 12 is reduced by 4 units upon being added with solution Y. If you added a strong acid to the strong base, all ions are present in the solution, yes? So every OH- is neutralised by every H+ for example, meaning the resultant pH should be 7. The resultant pH is only 8 however, so solution Y must be a <em>weak acid </em>only!
Missing question: Z:X = 7:1 A:Z = 2.5:1 A:Z = 2.2:1 Y:X = 11:1.
Answer is:<span> Z:X = 7:1 and Y:X = 11:1.
Law of multiple proportions or Dalton's Law
said that the ratios of the masses of the second element which
combine with a fixed mass of the first element will be ratios of small whole
numbers.
In this example ratios are whole numbers, A:Z = 2.5 : 1
and A:Z = 2.2 : 1 are not whole number ratios.</span>
Explanation:
mass = moles * molar mass
molar mass of carbon dioxide (CO2) = 12+32 = 44
= 19.5* 44 = 858
proof
moles = mass /molar mass
= 858/44 = 19.5 moles
The rate of a reaction would be one-fourth.
<h3>Further explanation</h3>
Given
Rate law-r₁ = k [NO]²[H2]
Required
The rate of a reaction
Solution
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.
Can be formulated:
Reaction: aA ---> bB

or

The concentration of NO were halved, so the rate :
![\tt r_2=k[\dfrac{1}{2}No]^2[H_2]\\\\r_2=\dfrac{1}{4}k.[No]^2[H_2]\\\\r_2=\dfrac{1}{4}r_1](https://tex.z-dn.net/?f=%5Ctt%20r_2%3Dk%5B%5Cdfrac%7B1%7D%7B2%7DNo%5D%5E2%5BH_2%5D%5C%5C%5C%5Cr_2%3D%5Cdfrac%7B1%7D%7B4%7Dk.%5BNo%5D%5E2%5BH_2%5D%5C%5C%5C%5Cr_2%3D%5Cdfrac%7B1%7D%7B4%7Dr_1)
The cell notation is:

here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell
in anodic half cell : oxidation takes place [loss of electrons]
in cathodic half cell: reduction takes place [gain of electrons]
1) this is a galvanic cell
2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode


Therefore

3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative
Δ
As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.