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damaskus [11]
3 years ago
11

Question: A car (assumed to be a Ford Taurus) is traveling around a turn that is banked at 7 degrees. The turn has a radius of 2

9 m. The car has a mass of 1300 kg. The coefficient of static friction between the tires and the road is 0.68.
1. What is the "ideal speed?" That is, what speed would allow the car to make the turn without requiring friction?

2. What is the maximum speed the car can go around the turn without sliding?

Physics
1 answer:
AysviL [449]3 years ago
6 0

Answer:

Question: A car (assumed to be a Ford Taurus) is traveling around a turn that is banked at 7 degrees. The turn has a radius of 29 m. The car has a mass of 1300 kg. The coefficient of static friction between the tires and the road is 0.68.

1. What is the "ideal speed?" That is, what speed would allow the car to make the turn without requiring friction?

2. What is the maximum speed the car can go around the turn without sliding?

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Where T is the period. Since the two accelerations have to be equal, we obtain:

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This has interesting applications. In the Solar System, for example, if you know the period and the radius of one planet orbit, by knowing another planet's period you can determine its orbit radius. I hope that this answers your question.


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Explanation:

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KE=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2KE}{m}} \\\\v=\sqrt{\dfrac{2\times 3.59\times 10^{-20}}{9.1\times 10^{-31}}} \\\\v=2.8\times 10^5\ m/s

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Mashcka [7]

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