Question: A car (assumed to be a Ford Taurus) is traveling around a turn that is banked at 7 degrees. The turn has a radius of 2
9 m. The car has a mass of 1300 kg. The coefficient of static friction between the tires and the road is 0.68.
1. What is the "ideal speed?" That is, what speed would allow the car to make the turn without requiring friction?
2. What is the maximum speed the car can go around the turn without sliding?
1. What is the "ideal speed?" That is, what speed would allow the car to make the turn without requiring friction?
2. What is the maximum speed the car can go around the turn without sliding?
1 answer:
You might be interested in
Answer:
D. The more the change in gravitational potential energy.
Explanation:
From Physics, we know that change in gravitational potential energy (), measured in joules, is directly proportional to change in height (
), measured in meters. Then, the higher her jump, the more the change in gravitational potential energy.
We cannot speak of elastic energy, since statement of the problem does not speak of any deformable system (i.e. spring) in any form.
Therefore, the correct answer is D.
Answer:
The value is
Explanation:
From the question we are told that
The radius is
The coefficient of static friction is
Generally the maximum safe driving speed is mathematically represented as
=>
=>
Answer:
The light enters the box along the normal to the side of the box or perpendicularly to the box's surface
Therefore, the light is expected to travel straight through the box
However, when a rectangular glass prism is placed inside the box, the light can then be refracted to pass through the box in the given path as shown
Light bends towards the normal when passing from a less dense medium to a denser medium with larger refractive index and vice versa
Therefore, when the glass prism with a larger refractive index than air is inclined with the top part further away from the incident beam and the bottom part closer to the incident beam as shown, the refracted ray through the box will be shifted downwards as shown in the drawing created with Microsoft Visio
Explanation:
Where;
i = The angle between the incidence light and the normal line
r = The angle between the refracted light and the normal line
n = The refractive index
When n > 1 is large, we have, ∠i > ∠r and the light is bent towards the normal when moving from a less dense medium to a denser medium and vice versa.
