All categories

3 years ago

What is the experimental setup?

Chemistry

2 answers:

WARRIOR [948]3 years ago

8 0

Answer:

What is the experimental setup? When you set up an experiment, you have to have one set up where you introduce the independent variable (the experimental set up) and one where you do not (the control). The two groups are treated EXACTLY alike except for the ONE variable being tested.

Explanation:

도움이 되셨길 바라며...안전하세요✨

Mrac [35]3 years ago

8 0

Answer:

When you set up an experiment, you have to have one set up where you introduce the independent variable (the experimental set up) and one where you do not (the control). The two groups are treated EXACTLY alike except for the ONE variable being tested.

You might be interested in

What scientists do that is the basis for their investigations

ivann1987 [24]

Scientists ask questions, which is the basis for their investigations.

8 0

3 years ago

Read 2 more answers

2.50 L of a gas at standard temperature and pressure is compressed to 575 mL. What is the new pressure of the gas

vfiekz [6]

Answer:

4.35 atm

Explanation:

According to the information given;

Initial volume of the gas, V₁ is 2.50 L
Initial pressure of the gas is standard pressure P₁, normally 1 atm
New volume of the gas, V₂ is 575 mL

We are required to determine the new pressure of the gas, P₂ ;

To answer the question, we are going to use the Boyle's law, that relates pressure and volume at constant temperature.

According to Boyle's law;

P₁V₁ = P₂V₂

Therefore, to determine the new pressure, P₂, we rearrange the formula;

New pressure, P₂ = P₁V₁ ÷ V₂

Thus;

P₂ = ( 1 atm × 2.50 L) ÷ 0.575 L

= 4.3478 atm

= 4.35 atm

Therefore, the new pressure of the gas is 4.35 atm

6 0

3 years ago

Read 2 more answers

Calculate the molarity of 0.060 moles NaHCO3 in 1500. mL of solution

Jobisdone [24]

Answer:

= 0.4 M

Explanation:

data:

moles = 0.060 moles

volume = 1500 ml

= 1500 / 1000

= 1.5 dm^3

solution;

molarity = $\frac{no. of moles}{volume in dm^3}$

= 0.060 / 1.5

molarity = 0.4 M

5 0

2 years ago

All of the following reactions can be described as displacement reactions except:____________.

Lady_Fox [76]

Answer:

Explanation:

The reaction that is not a displacement reaction from all the options is $C_6H_6_{(l)} + Cl_{2(g)} --> C_6H_5Cl_{(l)} + HCl_{(g)}$

In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.

<em>Options a, c, d, and e involves the displacement of a part of one of the reactants by another reactant while option b does not.</em>

Correct option = b.

8 0

3 years ago

Within a conventional light bulb,

aniked [119]

Answer:

Explanation:

Solid, Liquid and Gas are the states of matter. Light is neither a solid, a liquid, nor a gas.

4 0

3 years ago