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Dmitriy789 [7]
3 years ago
5

How do I do balancing equations

Chemistry
1 answer:
OlgaM077 [116]3 years ago
7 0

Explanation:

To balance any chemical equation, you must first understand the law of conservation of mass.

The law of conservation of mass states that "atoms are neither created nor destroyed in a chemical reaction but are changed from one form to another".

So in any chemical reaction the number atoms on both sides of the equation must be the same.

    To balance a chemical equation:

  • you can inspect the given equation and fix appropriate whole number coefficient to chemical species that are not balanced.
  • Also you can set up simple and solvable algebraic equations.

For example:

       aNa + bCl₂  →  cNaCl

a, b and c are the coefficients that will balance the equation;

     conserving: Na     a  = c

                          Cl      2b = c

let b = 1

     c = 2

      a = 2

                    2Na + Cl₂  →  2NaCl

learn more

Balanced equation brainly.com/question/2947744

#learnwithBrainly

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What is the molar mass of 1-butene if 5.38 × 1016 molecules of 1-butene weigh 5.00 μg?
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<h3>Answer:</h3>

             Molar Mass =  56 g.mol⁻¹

<h3>Explanation:</h3>

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                   Mass  =  5.00 μg  =  5.0 × 10⁻⁶ g

                   Number of Molecules  =  5.38 × 10¹⁶ Molecules

Step 1: Calculate Moles of 1-Butene:

                      As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

                          Number of Moles  =  Number of Particles ÷ 6.022 × 10²³

Putting values,

                          Number of Moles  =  5.38 × 10¹⁶ Molecules ÷ 6.022 × 10²³

                          Number of Moles  =  8.93 × 10⁻⁸ Moles

Step 2: Calculate Molar Mass of 1-Butene:

As,

                          Mole  =  Mass ÷ M.Mass

Solving for M.Mass,

                          M.Mass  =  Mass ÷ Mole

Putting values,

                          M.Mass  =  5.0 × 10⁻⁶ g ÷ 8.93 × 10⁻⁸ mol

                          M.Mass =  55.99 g.mol⁻¹ ≈ 56 g.mol⁻¹

4 0
3 years ago
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