Answer:
88.50 %
The balance chemical equation is as follow,
2 H₂ + O₂ → 2 H₂O
Step 1: Find the limiting reactant;
According to eq.
4.032 g (2 mole) H₂ reacts with = 32 g (1 mole) of O₂
So,
11 g of H₂ will react with = X g of O₂
Solving for X,
X = (11 g × 32 g) ÷ 4.032 g
X = 87.301 g of O₂
Therefore, H₂ is the limiting reactant as O₂ is present in excess.
Step 2: Calculating %age Yield;
According to eq.
4.032 g (2 mole) H₂ produces = 36.032 g (1 mole) of H₂O
So,
11 g of H₂ will react with = X g of H₂O
Solving for X,
X = (11 g × 36.032 g) ÷ 4.032 g
X = 98.301 g of H₂O
So,
Actual Yield = 87 g
Theoretical Yield = 98.301 g
Using formula = Actual Yield / Theoretical Yield × 100
= 87 g / 98.301 × 100
= 88.50 %
Answer:
The percent yield is 70.486%
Explanation:
Hence, the percent yield is 70.486%
The answer is without access to energy
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