Answer:
SeCl₆ < SeF₂ < SeO₂
Explanation:
To determine the order of the bond angle of the compound, we need to determine the hybridization of each compound given.
For:
SeO₂, The hybridization is sp² because the Se is doubly bonded to O at both sides and Se contains a lone pair of electrons.
SeCl₆, Se is attached to six different Cl atoms via a single bond in a hexagonal shape. Thus, SeCl₆ hybridization is sp³d²
SeF₂, Here, Se is singly bonded to F atoms on both sides and Se contains a lone pair of electrons. The hybridization is sp³
Therefore, the bond angle in sp² = 120°, sp³ = 109.8°, sp³d² = 90°
Hence, the order is: SeCl₆ < SeF₂ < SeO₂
<span>2 C2H6(g) + 5 O2(g) --------> 4 CO(g) + 6 H2O(g)
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After the addition of 6.47 mL of 0.303 M HCl. Solution :- lets first calculate the moles of the NaOCl and HCl Moles = molarity *volume in liter Moles of NaOCl = 0.100 mol per L * 0.053 L =0.0053 mol Moles of HCl =0.303 mol per L *0.00647L=0.00196
Yes, It is important to know the volume of Unknown acid or base to be titrated.
Titration is carried out in order to find out the concentration (i.e. molarity) of unknown acid or base. In this process a standard solution of acid or base is taken and is titrated with known volume of of titrant. At end point (neutralization) the amount of standard titrant utilized is calculated and following formula is employed to calculate the unknown concentration of unknown solution.
M₁V₁/n₁ = M₂V₂/n₂
