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taurus [48]
3 years ago
13

Question 044 Which of the following sequences converts 2-methylpropene and sodium acetylide into 3-methylbutanal? 1) HBr; 2) NaC

CH; 3) O3; 4) DMS 1) NaCCH; 2) H2/Ni2B; 3) O3; 4) DMS 1) HBr, ROOR; 2) NaCCH; 3) H2/Ni2B 4) O3; 5) DMS 1) HBr, ROOR; 2) NaCCH; 3) O3; 4) H2O 1) HBr; 2) NaCCH; 3) O3; 4) H2O
Chemistry
2 answers:
Minchanka [31]3 years ago
8 0

Answer:

1) HBr; 2) NaCCH; 3) O3; 4) H2O

Explanation:

The first step is formation of alkyl halide followed by reaction with sodium acetylide, to form 3-methylbutene, which is then followed by oxidation reaction with O3& H2O to 3-methylbutanal

Kruka [31]3 years ago
6 0

Answer:

The sequence of reagents' incorporation for the conversion of 2-methylpropene into 3-methylbutanal is <u>option (C.):</u>

1. HBr,ROOR ; 2.  NaCCH,H_{2}/Ni_{2}B ; 3. O_{3}, DMS

Explanation:

The summary of this reaction's mechanism is as follows:

  • <em>Radical hydro-halogenation</em> of 2-methylpropene through a technique known as <em>"peroxide effect"</em> in which the HBr addition causes free radical formation of the alkene
  • <em>Nucleophilic SN2 substitution </em>reaction (acetylide)
  • <em>Hydrogenation</em>
  • <em>Ozonolysis of the alkene</em>: after the addition reaction, the intermediate ozonide is converted to aldehyde using dimethyl sulfide (DMS)
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7 0
3 years ago
I need help with my homework.Calculate the number of formula units in: 41.5 grams CaBr2
lana66690 [7]

Answer:

\text{ }1.25\times10^{23}\text{ formula units}

Explanation:

Here, we want to calculate the number of formula units in the given molecule

We start by getting the number of moles

To get the number of moles, we have to divide the mass given by the molar mass

The molar mass is the mass per mole

The molar mass of calcium bromide is 200 g/mol

Thus, we have the number of moles as follows:

\frac{41.5}{200}\text{ = 0.2075 mol}

The number of formula units in a mole is:

1\text{ mole = 6.02 }\times10^{22}\text{ formula units}

The number of formula units in 0.2075 mole will be:

0.2075\text{ }\times6.02\times10^{23}\text{ = }1.25\times10^{23}\text{ formula units}

5 0
1 year ago
a titration of 25.0mL of an x M hcl solution with 0.15M NaOH starts at a burette reading for NaOH of 0.20mL . Thr burette readin
VARVARA [1.3K]
Burette is a very accurate measuring instrument when adding solutions and has a measurement error of 0.05 mL. 
Small volumes of solutions can be transferred from the burette at a controllable rate. 
In this instance NaOH is in the burette.
Initial reading of NaOH is 0.20 mL 
end point is the point at which the chemical reaction reaches completion. In acid base reactions, end point is when all the H⁺ ions have reacted with OH⁻ ions. 
final reading of NaOH is 24.10 mL
to find the volume of NaOH dispensed we have to find the difference between final reading and initial reading 
volume of NaOH added = 24.10 mL - 0.20 mL = 23.90 mL
volume of NaOH dispensed is 23.90 mL
6 0
3 years ago
For the reaction of sodium bromide with chlorine gas
lina2011 [118]

The reaction of sodium bromide with chlorine gas is Cl₂(aq) + 2Na + 2Br? 2Na + 2Cl⁻ + Br²(aq).

<h3>What is sodium bromide?</h3>

Sodium bromide is an inorganic compound, white, crystalline with high melting point.

The reaction between halogens is redox reaction

Oxidation  – 2Br⁻ ? Br₂ + 2e⁻ loss of electron.

Reduction – Cl₂ + 2e⁻ ? 2Cl⁻ gains of electron.

Thus, the correct option is Cl₂(aq) + 2Na + 2Br? 2Na + 2Cl⁻ + Br²(aq).

Learn more about sodium bromide

brainly.com/question/15409724

#SPJ4

7 0
2 years ago
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