The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.
The reaction is:
2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O (1)
The enthalpy of reaction (1) is given by:
(2)
Where:
r: is for reactants
p: is for products
The bonds of the compounds of reaction (1) are:
- 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
- 7O₂: 7 moles of 1 O=O bond
- 4CO₂: 4 moles of 2 C=O bonds
- 6H₂O: 6 moles of 2 H-O bonds
Hence, the enthalpy of reaction (1) is (eq 2):

Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.
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Answer:
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Reduction is the process by which eletrons are gained by an atom.
B) convection
Explanation:
Once the sun's energy reaches the earth's atmosphere by radiation, it is circulated within the atmosphere and oceans through convection.
The energy of the sun on earth is moved between the ocean and the atmosphere by air around us.
- Heat transfer in fluids is by convection.
- It involves the actual motion of the particles of medium from one place to another due to differences in temperature and density.
- Air close to the surface of the ocean is less dense and hot due to high temperature.
- The air rises and it is replaced by colder air masses.
- This exchange leads to the development of convective cells.
- This moves the energy of the sun between the atmosphere and the ocean surface.
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