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2 years ago

What is centripetal forcehello

Physics

2 answers:

Gwar [14]2 years ago

8 0

Answer:

A centripetal force is a net force that acts on an object to keep it moving along a circular path

Bond [772]2 years ago

5 0

Answer:

A force that acts on a body moving in a circular path and directed towards the centre around which the body is moving is called Centripetal force.

Explanation:

When an object travels around a circular path with a constant speed, it experiences an accelerating centripetal force towards the centre.

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A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V house

zhenek [66]

1. increase, 2. decrease

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3 years ago

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astra-53 [7]

Answer:

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2 years ago

A uniform-density 7 kg disk of radius 0.21 m is mounted on a nearly frictionless axle. Initially it is not spinning. A string is

GREYUIT [131]

Answer:

$\omega = 22.67 rad/s$

Explanation:

Here we can use energy conservation

As per energy conservation conditions we know that work done by external source is converted into kinetic energy of the disc

Now we have

$W = \frac{1}{2}I\omega^2$

now we know that work done is product of force and displacement

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$W = F.d$

$W = (44 N)(0.9 m) = 39.6 J$

now for moment of inertia of the disc we will have

$I = \frac{1}{2}mR^2$

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2 years ago

Read 2 more answers

A 75-m-long train begins uniform acceleration from rest. the the train has a speed of 23 m/s when it passes a railway worker tan

Lapatulllka [165]

Answer:

acceleration a = 1.04 m/s2

Explanation:

Assume the train has a speed of 23m/s when the last car passes the railway workers. Once this happens the last car would have traveled a total distance of the 180m distance between the railway worker standing 180 m from where the front of the train started plus the 75m distance from the first car to the last car:

s = 75 + 180 = 255 m

We can use the following equation of motion to find out the distance traveled by the car:

$v^2 - v_0^2 = 2as$ where v = 23 m/s is the velocity of the car when it passes the worker, $v_0$ = 0m/s is the initial velocity of the car when it starts, a m/s2 is the acceleration, which we are looking for.