The frequency of oscillation on the frictionless floor is 28 Hz.
<h3>
Frequency of the simple harmonic motion</h3>
The frequency of the oscillation is calculated as follows;
f = (1/2π)(√k/m)
where;
- k is the spring constant
- m is mass of the block
f = (1/2π)(√7580/0.245)
f = 28 Hz
Thus, the frequency of oscillation on the frictionless floor is 28 Hz.
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Answer:
f = 400 / 5 s = 80/sec frequency of revolution
P = 1/f = 1/(80/sec) = .0125 sec period of revolution
Answer:
the aircraft must travel at a speed of <em>73.4 m/s</em> in order to create the ideal lift.
Explanation:
We will use Bernoulli's theorem in order to determine the pressure lift:
ΔP = 1/2 (ρ)(v₂² - v₁²)
the generated pressure lift is ΔP = 1000 N/m²
Therefore,
1000 = 1/2(ρ)(v₂² - v₁²)
v₂² - v₁² = 2000 / ρ
v₂² = (2000 N/m² / 1.29 kg/m³) + (62 m/s)²
v₂ = √[ (2000 N/m² / 1.29 kg/m³) + (62 m/s)² ]
<em>v₂ = 73.4 m/s </em>
<em></em>
Therefore, the aircraft must travel at a speed of <em>73.4 m/s</em> in order to create the ideal lift.
Kinetic energy=1/2mv^2
=1/2(142*10^-3)(42.9)^2=130.6=131J
The period will be the same if the amplitude of the motion is increased to 2a
What is an Amplitude?
Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.
Here,
mass m is attached to the spring.
mass attached = m
time period = t
We know that,
The time period for the spring is calculated with the equation:
Where k is the spring constant
Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.
From the equation, we can say,
Time period of the spring is independent of the amplitude.
Hence,
Increasing the amplitude does not affect the period of the mass and spring system.
Learn more about time period here:
<u>brainly.com/question/13834772</u>
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