A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at
the other end as shown. The cable is attached at a height H=1.70 m above the pivot and the plank's CM is located a distance d=0.700 m from the pivot.
Calculate the tension in the cable.
Calculate the tension in the cable.
1 answer:
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Answer:
7.1 Hz
Explanation:
In a generator, the maximum induced emf is given by
where
N is the number of turns in the coil
A is the area of the coil
B is the magnetic field strength
f is the frequency
In this problem, we have
N = 200
B = 0.030 T
So we can re-arrange the equation to find the frequency of the generator:
Answer:
Explanation:
Given
time taken
Speed acquired in 2 sec
Here initial velocity is zero
acceleration is the rate of change of velocity in a given time
Distance travel in this time
where
s=displacement
u=initial velocity
a=acceleration
t=time
so Jet Plane travels a distance of 42 m in 2 s