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Lynna [10]
3 years ago
9

An 8.0g bullet, moving at 400 m/s, goes through a stationary block of wood in 4.0 x 10^-4s, emerging at a speed of 100 m/s. (a)

what average force did the wood exert on the bullet? (b) how thick is the wood?
Physics
1 answer:
Ierofanga [76]3 years ago
7 0

Answer:

Explanation:

Initial velocity (u) of the Bullet = 400 m/sec

Final velocity (v) of the Bullet = 100 m/sec

Bullet passed through the block in (t) = 0.0004 sec  

Using 1st Equation of motion :

400 m/s = 100 m/s - a (0.0004)

<em>Deceleration of Bullet = 750,000 m/sec^2 </em>

<em />

(a) F (force exerted by the wooden block on the bullet) = F (force exerted by the bullet on the wooden block)

F = m * a = 0.008 * 750,000<em> = </em>6000 N

(b) Using 3rd Equation of motion :

v^{2} = u^{2} - 2aS

10000 = 160000 - 2 * 750,000 * S

Thickness of wood (S) = 0.1 m

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Protons and neutrons are the only subatomic particles with mass, and they are located in the nucleus. If this atom has an atomic number of 29 and is copper, it must have 29 protons (protons define which element is being observed). This means all remaining mass is from neutrons. 64-29 = 35.

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Neon atoms at 245 K pass through a fan that gives each mole of neon gas an additional kinetic energy of 16.0 J. Part A What is t
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246.28 K

Explanation:

The total energy of one mole of gas molecules can be calculated by the formula given below

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Total energy of gas molecules = 3055.4 + 16 = 3071.4 J.

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Answer:

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We have to find the distance at which electric field is 2.45 N/C

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