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3 years ago

Does a Magnesium atom gains 2 electrons in an ionic compound?

Physics

1 answer:

andrew-mc [135]3 years ago

6 0

Answer:

Yes

Explanation:

Example of ionic bonding takes place between magnesium(mg) and oxygen(02) to form magnesium oxide (mg0).... Magnesium loses two electrons to form Mg2+, and oxygen gains two electrons to form 02-

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In Ohm's Law, it states that the current in the circuit is directionally proportional to the voltage in that circuit. Explain wh

tester [92]

Answer:

Explanation:

Well mathematically it would look like this

E = k * I

k is the constant of proportionality.

As the voltage goes up, so does the current.

As the voltage goes down, so does the current.

In physics and engineering,, the formula is written somewhat differently.

E = I * R

The R is a device which limits the current. If R = 0 (like it is just a switch closing) then the first thing you will notice is that the lights go out and you better know where the circuit breakers are and have a flashlight to see which one you shorted out.

So R has a value > 0 in practice.

5 0

3 years ago

What is the density of an object with a mass of 60g and a volume of 2cm3?

zaharov [31]

m= 60g = 60/1000 Kg = 0.06 Kg v = 2cm3 = 2 * (0.01^3) m3 = 2 *10^-6 m3 Density= m/v = 6 * 10^-2 / 2 *10^-6 = 3 *10^4 Kg/m3

8 0

3 years ago

Given an electron beam whose electrons have kinetic energy of 10.0 kev , what is the minimum wavelength λmin of light radiated b

kolbaska11 [484]

To answer the problem we would be using this formula which isE = hc/L where E is the energy, h is Planck's constant, c is the speed of light and L is the wavelength
L = hc/E = 4.136×10−15 eV·s (2.998x10^8 m/s)/10^4 eV

= 1.240x10^-10 m

= 1.240x10^-1 nm

3 0

4 years ago

Read 2 more answers

A ball is rolled at an initial speed of 5 m/s and finishes a certain distance at a speed of 7 m/s. if the ball rolled for 9 seco

Setler79 [48]

Answer:

The ball rolled a distance of 54 m.

Explanation:

Given:

Initial velocity of the ball is, $u=5\ m/s$

Final velocity of the ball is, $v=7\ m/s$

Time for rolling is, $t=9\ s$

The distance of rolling is, $S=?$

First, let us find the acceleration of the ball using Newton's equation of motion as:

$v=u+at\\a=\frac{v-u}{t}\\a=\frac{7-5}{9}=\frac{2}{9}\ m/s^2$

Now, displacement of the ball can be determined using the following equation of motion:

$v^2=u^2+2aS$

Rewriting the above in terms of 'S', we get

$S=\frac{v^2-u^2}{2a}$

Plug in the known values and solve for 'S'. This gives,

$S=\frac{7^2-5^2}{2\times \frac{2}{9}}\\\\S=\frac{49-25}{\frac{4}{9}}\\\\S=\frac{9\times 24}{4}\\\\S=9\times 6=54\ m$

Therefore, the ball rolled a distance of 54 m.

3 0

4 years ago

What are some of the names given to the Moon by the Algonquin?

frutty [35]

The names given to the Moon by the Algonquin are as follows:

January- Full Wolf Moon
February- Full Snow Moon
March- Full Worm Moon
April- Full Pink Moon
May- Full Flower Moon
June- Full Strawberry Moon
July- Full Buck Moon
August- Full Sturgeon Moon
September- Full Corn Moon; Full Harvest Moon
October- Full Hunter's Moon
November- Full Beaver Moon
December- Full Cold Moon; Full Long Nights Moon

6 0

3 years ago