We know that a=vf_vi/t equals equation "a" . Where a is the acceleration of the body , vf is the final velocity , vi is the initial velocity and t is equal to time . Since vi equals o m/s , vf equals to 60 m/s and t equals 10 s. Put in equation "a". a=60-0/10 =6m/s2
Answer:
Explanation:
v = Velocity of the elevator = 3.1 m/s
= Angle of the slope = 
Vertical component is given by
The vertical component of the velocity is .
Horizontal component is given by
The horizontal component of the velocity is .
Answer:
1850 N
Explanation:
The formula for friction force between the load and plane is given as ;
F= μ*N
N = mg cos θ
To find θ, which is the angle the inclined plane makes with the ground at the height of 1.5 m
Sin θ = 1.5/4.5
Sin θ = 0.3333
Sin⁻{0.3333} = 19.50°
θ = 19.50°
Finding N , where m= 500 N , and g= 9.81
N = mg cos θ
N= 500 * 9.81 * cos 19.50°
N= 4624 N
Coefficient of kinetic friction is calculated as;
μ=F/W
μ = 200/500 = 0.4
The magnitude of kinetic friction is given as;
Fk= μ * N
Fk = 0.4 * 4624
Fk= 1850 N
