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3 years ago

Does a Magnesium atom gains 2 electrons in an ionic compound?

Physics

1 answer:

andrew-mc [135]3 years ago

6 0

Answer:

Yes

Explanation:

Example of ionic bonding takes place between magnesium(mg) and oxygen(02) to form magnesium oxide (mg0).... Magnesium loses two electrons to form Mg2+, and oxygen gains two electrons to form 02-

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A thin partition divides a thermally insulated vessel into a lower compartment of volume V and an upper compartment of volume 2V

Anni [7]

Answer:

1.89mol

Explanation:

The entropy change during free expansion is express as

$S_{f}-S_{i}=nRln(\frac{V_{F}}{V_{I}})\\$

Where S is the entropy of the system,

n is the amount of mole

R is the gas constant = 8.314 and

V is the volume occupied at the initial and final stage

since the process is n adiabatic free expansion, the entropy of the system is constant. Hence we can re-write the equation as

$S=nRln(\frac{V_{F}}{V_{I}})\\$

where the $V_{i}=v\\$ and $V_{f}=2v+v=3v\\$

$S=17.28J/k\\$ and

$R=8.314\\$

Now if we substitute in values we arrive at

$17.28=(8.314)n*ln(\frac{3v}{v} )\\17.28=(8.314)n*ln(3 )\\17.28=(8.314)n*1.0986\\n=\frac{17.28}{8.314*1.0989}\\n=1.89 mole\\$

6 0

3 years ago

A book is pushed with an initial horizontal velocity of 5.0 meters per second off the top of a desk. What is the initial vertica

PSYCHO15rus [73]

Answer:

The Initial vertical velocity is zero

Explanation:

Given that,

A book is pushed with an initial horizontal velocity, Vx = 5 m/s

According to projectile motion, the horizontal component of velocity i.e., in X-axis remains the same though out its path.

The vertical velocity varies i.e., the velocity towards the Y- axis.

The velocity of the falling book in its trajectory is the resultant velocity. Due to the action of gravity, it keeps on increasing with time.

The resultant velocity is given by relation

$V_{R} = \sqrt{{V_{x}^{2}} +[ {gt}]^{2} }$

where

gt = Vy - vertical velocity

g - acceleration due to gravity

t - time

Since, the initial horizontal velocity at that instant is equal to the resultant velocity.

Vx = 5 m/s

$V_{R}$ = 5 m/s

So, on substituting in the above equation

Vy = 0 m/s

Therefore, the initial vertical velocity is equal to zero

7 0

3 years ago

What happens when an electric charge passes through a circuit?

sleet_krkn [62]

Answer:

The electric field direction within a circuit is by definition the direction that positive test charges are pushed. Thus, these negatively charged electrons move in the direction opposite the electric field.

Explanation:

: )

5 0

3 years ago

Read 2 more answers

Help plzzz, if a question has more than one answer, pur both letters! Plzz I need 5 letters, this is the third time I’m posting

Kaylis [27]

Answer:

1) e

2)c

3)b

4)d

i dont know if these are right, but something along these lines if you understand the pattern

Explanation:

4 0

3 years ago

A Rac variant, in which the residue at position 61 was replaced with an alanine (Rac61A), was synthesized. Wild-type Rac and Rac

ludmilkaskok [199]

Answer:

Ammonia, $(NH_{3})$

Explanation:

If a Rac variant, in which the residue at position 61 was replaced with an alanine (Rac-61A), was synthesized. Also, Wild-type Rac and Rac-61A were incubated separately with VopC.

In order to obtain data to support that VopC modifies Rac at residue 61, the samples should be analyzed for the presence of Ammonia ( $NH_{3}[\tex]) compound.In chemistry, the Vanadyl Phthalocyanine (VopC) comprises of a catalytic domain that activates host cells GTPase Rac irreversibly, through the deamide side chain of the residue existing at position 61.Also, we know that a deamidation reaction gives off Ammonia, [tex](NH_{3})$ and as such when ammonia is present in the sample containing Wild-type Rac but not in Rac-61A, this simply proves or provide the data to support that VopC modifies Rac at residue 61.

<em>Additionally, deamidation can be defined as the chemical conversion (hydrolysis) of an amide functional group such as glutamine, asparagine, in a polypeptide to another functional group such as glutamic acid or isoaspartic acid respectively by treating it with a strong acid (deamidate, transamidase). </em>

3 0

3 years ago