Answer:
3.75 m/s
Explanation:
Given that a bumblebee is flying to the right when a breeze causes the bee to slow down with a constant leftward acceleration of magnitude 0.50 m/s^2. After 2.0 s the bee is moving to the right with a speed of 2.75 m/ s
What was the velocity of the bumblebee right before the breeze?
Since the breeze blows with the acceleration of 0.5 m/s^2 for 2 seconds, we can calculate the magnitude of the velocity at which it moves.
Acceleration = velocity/ time
Substitute the acceleration and time into the formula
0.5 = V/2
Cross multiply
V = 2 × 0.5
V = 1 m/s
The bumblebee is travelling right ward while the wind travels leftward.
The relative velocity = 2.75 m/s
Let the bumblebee speed = Vb
While the wind = VW
Vb - Vw = 2.75
Substitute the wind speed into the formula
Vb - 1 = 2.75
Vb = 2.75 + 1
Vb = 3.75 m/s
Therefore, the velocity of the bumblebee right before the breeze is 3.75 m/s
<span>Compared to radio waves, ultraviolet rays have relatively much much
much much much shorter wavelengths and higher frequencies.</span>
Answer:
12.5 grams
Explanation:
From the question,
E' = E/2⁽ⁿ/a⁾....................... Equation 1
Where E' = mass left, E = Original mass, n = time, a = half-life.
Given: E = 200 grams, n = 40 years, a = 10 years.
Substitute these values into equation 1
E' = 200/2⁽40/10⁾
E' = 200/2⁴
E' = 200/16
E' = 12.5 grams.
Hence 12.5 grams of the isotope will be left.
Answer:
0.435 m/s
Explanation:
Assuming that the missing sketch is what I've attached,
length of the handle = 0.2 m
Tangential speed (v) = 1.74 m/s
angular speed 
The rod where bucket tied through the rope
Radius = 0.1/2 = 0.05 m
v= 8.7*0.05 = 0.435 m/s
the answer i think is when frozen rain moves up and down within an anvil cloud
hope this helps
