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wolverine [178]
3 years ago
8

ICl has a higher boiling point than Br2. What is the best explanation for this?

Physics
1 answer:
Vsevolod [243]3 years ago
7 0
Iodine Monochloride (ICI) is an interhalogen or compound. ICI has an intermolecular attraction which makes it more difficult to boil compare to Bromine (Br2). Brorime is among the halogens along with fluorine, chlorine, iodine and astatine. Bromine is a nonpolar substance while ICI is a polar compound.
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A property unique to a conducting substance that determines its resistance is called:
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Answer:

B. Resistivity

Explanation:

Resistance offered by a substance of unit area per unit length.

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HELP ME PLEASE!!!!!!!!!
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As per the given Figure attached here we know that both charges q1 and q2 will apply same force on charge q3 and hence the resultant force due to both charges will be along Y axis vertically upwards

So here we know that

F = \frac{kq_1q_3}{d_{13}^2}

now from the above equation

F = \frac{(9\times 10^9)(2\times 10^{-6})(4 \times 10^{-6})}{0.5^2}

F = 0.288 N

so both of the charges will apply 0.288 N force on q3 charge along the line joining them

now the net force due to vector sum is given by

F_{net} = 2Fcos\theta

here we know that angle is

\theta = 37 degree

now we have

F_{net} = 2\times 0.288 cos37

F_{net} = 0.46 N

so net force on q3 is 0.46 N vertically upwards along +Y axis

6 0
3 years ago
The forces acting on this object are _______ and the net force is ________ Balanced, 0 N Balanced, 10 N Unbalanced, 10 N Unbalan
Amanda [17]
1st Blank Answer: Balanced   
2nd Blank Answer: 0n 

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A demographic tool used to predict a population's future growth is
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What is the intensity of a sound with a sound intensity level (SIL) 67 dB, in units of W/m^2?
vfiekz [6]

Answer:

The intensity of sound (I) = 3.16 x 10⁻⁶ W/m²

Explanation:

We have expression for sound intensity level (SIL),

              L=10log_{10}\left ( \frac{I}{I_0}\right )

Here we need to find the intensity of sound (I).

               L=10log_{10}\left ( \frac{I}{I_0}\right )\\\\log_{10}\left ( \frac{I}{I_0}\right )=0.1L\\\\\frac{I}{I_0}=10^{0.1L}\\\\I=I_010^{0.1L}

Substituting

          L = 67 dB and I₀ = 10⁻¹² W/m² in the equation

          I=I_010^{0.1L}=10^{-12}\times 10^{0.1\times 65}\\\\I_0=10^{-12}\times 10^{6.5}=10^{-5.5}=3.16\times 10^{-6}W/m^2

The intensity of sound (I) = 3.16 x 10⁻⁶ W/m²

8 0
3 years ago
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