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Bad White [126]
3 years ago
8

When a magnesium ribbon is heated in air the product former is heavier.on the other hand when potassium manganate(VII) is heated

in air the product formed is lighter.Explian the difference iin observation
Chemistry
1 answer:
vesna_86 [32]3 years ago
4 0

Answer: On heating, Magnesium forms its oxide; while potassium manganate(VII) decomposes

Explanation:

Magnesium Mg, on heating forms Magnesium oxide

2Mg(s) + O2(g) --> 2MgO

Potassium permanganate KMnO4, on heating decomposes to potassium manganate K2MnO4, manganese dioxide MnO2, and Oxygen gas O2.

2KMnO4 --> K2MnO4 + MnO2 + O2

The difference in observation is that, on heating, Magnesium forms its OXIDE as product; while potassium manganate(VII) decomposes, giving OFF most of its constituents and reducing its weight.

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How many moles of H2 are needed to produce 24 moles of NH3?
eduard

Answer:

36 mol of H2

Explanation:

The balanced equation of the reaction is given as;

3H2 + N2 --> 2NH3

From the reaction;

It takes 3 mol of H2 reacting with 1 mol  of N2 to form 2 mol of NH3

3 mol of H2 = 2 mol of NH3

x mol of H2 = 24 mol of NH3

x =  (24 * 3) / 2 = 36 mol of H2

3 0
3 years ago
Name:
faust18 [17]

Answer:

1. V = 1.47L

Explanation:

1) Using PV = nRT

Where;

P = pressure (atm)

V = volume (L)

R = gas constant (0.0821 Latmk mol)

n = number of moles

T = temperature (K)

To get number of moles, we say mole = mass/molar mass

Molar Mass of C2H2 = 12(2) + 1(2)

= 24 + 2 = 26g/mol

mole = 3.86/26

mole = 0.148mol

T (K) = 28.5°C + 273.15

T(K) = 301.65K

PV = nRT

2.5 × V = 0.148 × 0.0821 × 301.65

2.5V = 3.665

V = 3.665/2.5

V = 1.466

V = 1.47L

R =

PV = nRT

P1 V1\ n1 T1 =P2 V2/ n2 T2

1. What volume, will be occupied by 3.86 g of C2H2 gas (acetylene) at 2.50 atm and a temperature

of 28.5 °C?

2. A gas at 650.0 torr and 75 °C is cooled to 25 °C. What is the pressure of the gas after it has

cooled?

7 0
3 years ago
When calculating specific heat, what does the variable 'Q' represent?
LekaFEV [45]

Answer:

Heat Energy

Explanation:

Specific heat is the a thermodynamic property of the substances. When we have to raise the temperature of unit mass of a given substance by one degree, the heat we will require for this purpose is known as Specific Heat.

Specific heat is calculated using the following formula which relates the specific heat with Heat Energy and Temperature

Q=mcΔT

Where,

Q = Heat energy,

m = mass of the substance in Kg.,

c = Specific heat, and

ΔT = change in temperature in kelvins.

4 0
3 years ago
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That piece of lab equipment is called a scoopula.
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The ratio of the elements in a binary ionic compound are based on the element's _______________.
Sergio039 [100]
Answer is B.) Mass number!
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