All categories

2 years ago

Calculate the molarity of a NaOH solution that is prepared by diluting 100mL of 0.20M NaOH with 150mL of H2O.

Chemistry

1 answer:

lianna [129]2 years ago

3 0

Molarity of solution = 0.08 M

<h3>Further explanation </h3>

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution

$\tt M=\dfrac{n}{V}$

Where

M = Molarity

n = number of moles of solute

V = Volume of solution

mol of NaOH

$\tt mol=0.2~M\times 100~ml=20~mlmol=0.02~mol$

molarity

Volume of solution = 100 ml + 150 ml = 250 ml

$\tt M=\dfrac{0.02~mol}{0.250~L}=0.08$

You might be interested in

At what temp will a gas be at if you allow it to expand from an original 456 mL to 65°C to 3.4 L

alexira [117]

We use the gas law named Charle's law for the calculation of the second temperature. The law states that,
V₁T₂ = V₂T₁
Substituting the known values,
(0.456 L)(65 + 273.15) = (3.4 L)(T₁)
T₁ = 45.33 K

5 0

2 years ago

Read 2 more answers

Calculate the freezing point of a 0.08500 m aqueous solution of nano3. the molal freezing-point-depression constant of water is

Citrus2011 [14]

Depression in freezing point (Δ $T_{f}$ ) = $K_{f}$ ×m×i,
where, $K_{f}$ = cryoscopic constant = $1.86^{0} C/m$ ,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For $NaNO_{3}$ )

Thus, (Δ $T_{f}$ ) = 1.86 X 0.0085 X 2 = $0.03162^{0}C$

Now, (Δ $T_{f}$ ) = $T^{0}$ - T
Here, T = freezing point of solution
$T^{0}$ = freezing point of solvent = $0^{0}C$
Thus, T = $T^{0}$ - (Δ $T_{f}$ ) = - $0.03162^{0}C$

8 0

2 years ago

Read 2 more answers

1. When frequency increases energy:

liraira [26]

B

When frequency increases, as does the energy, but wavelength decreases. It also works vise versa; if wavelength were to increase, its frequency and energy will decrease.

8 0

2 years ago

What is an atomic number? An atomic mass?

mrs_skeptik [129]

Answer:

The atomic number is the number of the elements inside the periodic table and the mass is the weight or a number under the elements.

Explanation:

Correct me if I am wrong

4 0

2 years ago

Read 2 more answers

Which is the metric standard for measuring energy? Which unit is used for specific heat capacity? If you wanted to compare the a

DENIUS [597]

1. Which is the metric standard for measuring energy?

The metric standard for measuring of energy defined by the International System of Units is the joule (J), which is defined as the work done by a force of a newton in a displacement of one meter in the direction of force. So,

1 J = 1 N m = 1 kg·m²/s²

Calorie is also frequently used in scientific and technological applications. Calorie is a unit of thermal energy that is equivalent to the amount of heat needed to raise the temperature of 1 gram of water by 1 degree Celsius.

1 cal = 4,184 J

2. Which unit is used for specific heat capacity?

The specific heat capacity (c) is a physical quantity that is defined as the amount of heat (q) that must be supplied to the mass unit of a thermodynamic substance or system to raise its temperature by one unit. So,

c = q / m ΔT

where m is the mass of the substance and ΔT is the temperature increase.

In this way, as heat is a form of energy, the International System of Units expresses the specific heat in joules per kilogram and per kelvin (J kg⁻¹ K⁻¹). Another common unit, not belonging to the SI, is the calorie per gram and per degree centigrade (cal g⁻¹ ° C⁻¹).

3. If you wanted to compare the abilities of olive oil and peanut oil to gain or lose thermal energy, which unit would you use?

You should use units of specific heat capacity (J kg⁻¹ K⁻¹) since, as mentioned above, this is a physical quantity that measures the amount of heat that must be supplied to an specific mass of a substance or system to raise its temperature.

Heat is a thermal energy, so by using heat capacity units you can compare the ability of olive oil and peanut oil to gain or lose thermal energy by varying its temperature.

3 0

2 years ago

Read 2 more answers