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dmitriy555 [2]
3 years ago
9

Which type of acetylcholine receptor is present on postganglionic neurons

Chemistry
1 answer:
Sonja [21]3 years ago
4 0

Answer:

Mescarinic and Nicotinic

Explanation:

Postganglionic fibers can be present in both sympathetic and parasympathetic divisions, their main difference resides in how in the sympathetic division the postganglionic fibers are adrenergic and use norepinephrine (noradrenalin) as a neurotransmitter, in the parasympathetic division, on the other hand, fibers are cholinergic and use acetylcholine as a neurotransmitter, the<em> postganglionic neurons of sweat glands release acetylcholine for the activation of muscarinic receptors, another kind of receptor for acetylcholine are nicotinic receptors </em>that act as transmembrane sodium/potassium channels, while muscarinic receptors need to act through intracellular proteins.

I hope you find this informatiou useful and interesting! Good luck!

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PLEASE HELP ME WITH THIS QUESTION THIS FREAKING SUCKS
tigry1 [53]

Answer:

m = 0.122 m

Explanation:

Molality(m): A measure of the number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent.

\mathrm{Molality\:Formula}:\quad \mathrm m =  \dfrac{ mole\:of\:solute  }{ mass\:of\:solvent\:in\:kg  }

\mathrm m =  \dfrac{ mole}{ kg  }

\mathrm{Substitute\:the\:numbers\:into\:the\:"Molality\:Formula"}

\mathrm m =   \dfrac{ 0.250  }{ 2.05  }

\mathrm{Divide\:0.250\:by\:2.05\:and\:get\:0.12195122}

\mathrm m =   {0.12195122}

\mathrm{Round\:to\:the\:nearest\:thousandths\:place}

\mathrm m =   0.122

8 0
2 years ago
What volume of 15.6M NH4OH is needed to make 500. mL of 3.00M solution?
Mariana [72]

Answer:

V₁  = 96.2 mL

Explanation:

Given data:

Initial volume of NH₄OH required = ?

Initial molarity = 15.6 M

Final molarity = 3.00 M

Final volume = 500.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of NH₄OH

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

15.6 M ×V₁  =  3.00 M×500.0 mL

15.6  M ×V₁  = 1500 M.mL

V₁  = 1500 M.mL /15.6 M

V₁  = 96.2 mL

6 0
3 years ago
An iron fence is left unpainted, and it reacts with the oxygen in the air, forming rust. The formation of rust is an oxidation-r
trapecia [35]
I'm pretty sure it would be a chemical reaction.
5 0
3 years ago
Read 2 more answers
Acid base reaction is called nuetralization reaction why?​
Lesechka [4]

Answer:

Explanation:

You have an acid that is acidic or a base that is basic. When you mix the two, they form water (assuming those are bronsted-lowry acids and bases) which is neutral.

3 0
3 years ago
Read 2 more answers
2. What volume will 3.00 moles of nitrogen gas occupy at STP?
Amiraneli [1.4K]

Answer:

Answer: V=67.2 L

Explanation:

Ideal Gas Law: PV=nRT

P=1.00 atm (STP)

V=?

n=3.00 mol

R=0.08206Latm/Kmol

T=273.15 K (STP)

To find V, we would manipulate the equation to V=nRT/P

With significan figures, our answer is V=67.2 L.

4 0
3 years ago
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