Answer: There are several ways. The first that comes to mind is a pH meter. A pH electrode Is lowered into the solution, and (Assuming) the pH Meter has been properly calibrated, and the temperature of the solution is set to the calibration of the Meter, the pH can be read directly from an analogue scale or digital readout. Below 7 is acidic, 7 is Neutral, (like Pure Water), and over 7 is Alkaline, or Basic.
A useful, but less accurate method is the use of any number of “pH Indicator Solutions”, which are essentially a type of various colored dyes that change color within differing pH ranges. Usually, if the pH is unknown, a small amount of solution is removed from the container and tested separately - in a “well plate”, or similar method.
These types of dyes, or Indicator Solutions, can be dried upon strips of “pH indicator Paper”, which, depending upon the type can be very useful when carrying out more precisely arrived at pH tests like Titration.
Just to see if a solution is “Acid” or “Base”, Litmus paper is used; “a Red color shows Acidity, and a Blue color, a Base”; ergo, “An Acid Solution will turn Litmus Paper, Red”.
This is an application of osmotic pressure which is one of the colligative properties of substances. The formula of osmotic pressure is expressed as P = MRT where M is molarity , R is the gas constant and T is temperature. When M is equal to a total of 0.305 M and T is equal to 298 K , P should be equal to 7.46 atm
Answer:
by the VSEPR theory.
Explanation:
This question is asking for the bond angle of the 
bond in 
. The VSEPR (valence shell electron pair repulsion) theory could help. Start by considering: how many electron domains are there on the carbon atom between these two bond?
Note that "electron domains" refer to covalent bonds and lone pairs collectively.
- Each nonbonding pair (lone pair) of valence electrons counts as one electron domain.
- Each covalent bond (single bond, double bond, or triple bond) counts as exactly one electron domain.
For example, in , the carbon atom at the center of that bond has two electron domains:
- This carbon atom has two double bonds: one
bond and one 
bond. Even though these are both double bonds, in VSEPR theory, each of them count only as one electron domain. - Keep in mind that there are only four valence electrons in each carbon atom. It can be shown that all four valence electrons of this carbon atom are involved in bonding (two in each of the two double bonds.) Hence, there would be no nonbonding pair around this atom.
In VSEPR theory, electron domains around an atom repel each other. As a result, they would spread out (in three dimensions) as far away from each other as possible. When there are only two electron domains around an atom, the two electron domains would form a straight line- with one domain on each side of the central atom. (To visualize, consider the three atoms in this bond as three spheres on a stick. The central 
atom would be between the other atom and the 
atom.)
This linear geometry corresponds to a bond angle of .
Answer:
The statement is true.
Explanation:
&he pressure exerted by a liquid depends on the height of the liquid column. Where h is height and ρ is density. As the height increases, pressure will also increase.
