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3 years ago

Pre-lab setup (4 points):

2 answers:

5 0

Independent is what you are testing with. dependent is what you ARE testing. constant is the control so like for example the time, or the same material etc. tools should be on your paper depending on what lab it is :)

vladimir1956 [14]3 years ago

4 0

1. Independent - The thing that you change and measure.

2. Dependant - The change that happens due to the independant variable.

3. The control variable.

4. Things that you will need during your experiment will usually be given to you on a paper with a list of supplies you will need and sometimes a brief summary of the method.

Hope this helps :)

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13. What is the main purpose of a particle accelerator?

Ivanshal [37]

It speeds up small particles

5 0

4 years ago

Iron(III) oxide and hydrogen react to form iron and water, like this: (s)(g)(s)(g) At a certain temperature, a chemist finds tha

stepan [7]

The question is incomplete, here is the complete question:

Iron(III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 5.4 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, iron, and water at equilibrium has the following composition:

Compound Amount

$Fe_2O_3$ 3.54 g

$H_2$ 3.63 g

Fe 2.37 g

$H_2O$ 2.13 g

Calculate the value of the equilibrium constant for this reaction. Round your answer to 2 significant digits

Answer: The value of equilibrium constant for the given reaction is $2.8\times 10^{-4}$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

For hydrogen gas:

Given mass of hydrogen gas = 3.63 g

Molar mass of hydrogen gas = 2 g/mol

Volume of solution = 5.4 L

Putting values in above equation, we get:

$\text{Molarity of hydrogen gas}=\frac{3.63}{2\times 5.4}\\\\\text{Molarity of hydrogen gas}=0.336M$

For water:

Given mass of water = 2.13 g

Molar mass of water = 18 g/mol

Volume of solution = 5.4 L

Putting values in above equation, we get:

$\text{Molarity of water}=\frac{2.13}{18\times 5.4}\\\\\text{Molarity of water}=0.0219M$

The given chemical equation follows:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[H_2O]^3}{[H_2]^3}$

The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression. So, the concentration of iron and iron (III) oxide is not present in equilibrium constant expression.

Putting values in above equation, we get:

$K_c=\frac{(0.0219)^3}{(0.336)^3}\\\\K_c=2.77\times 10^{-4}$

Hence, the value of equilibrium constant for the given reaction is $2.8\times 10^{-4}$

7 0

3 years ago

Consider the reaction below. CO(g) + Cl2(g) « COCl2(g) What is the most likely effect to the forward reaction if there is an inc

marysya [2.9K]

Answer: the reaction rate of the forward reaction increases (although it is not among the options shown).

Explanation:

1) The equation given is:

CO (g) + Cl₂ (g) ⇄ COCl₂ (g)

2) The forward reaction is:

CO (g) + Cl₂ (g) → COCl₂ (g)

3) The stoichiometry is 1 mole + 1 mole → 1 mole

4) Analysis and conclusion:

The effect of change in the conditions of an equilibrium is foreseen using Le Chatelier's principle.

Le Chatelier's principle states that a system in equilibrium will act trying to compensate the distress applied to the system.

In this case, the distress is increase in pressure.

To compensate the increase in pressure the system must act by reducing the number of moles in the system. Since the forward reaction implies the conversion of two moles of reagents into one mole of product, the more the forward reaction progress the less the number of moles will be present in the system and so the more the compensation of the increase in pressure. So the forward raction is favored by the increase in pressure.

Favoring the forwar reaction means that its rate will incrase,

3 0

3 years ago

Read 2 more answers

Rank the elements in each of the following sets in order of increasing IE₁:

zavuch27 [327]

Explanation:

Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.

When we move across a period from left to right then there occurs a decrease in atomic size of the atoms. Therefore, ionization energy increases along a period.

But when we move from top to bottom in a group then there occurs an increase in size of the atoms. Hence, ionization energy decreases along a group.

(a) As Sb, Sn and I are all period 5 elements. Hence, these elements are arranged in order of increasing $IE_{1}$ as follows.

Sn < Sb < I

(b) As Sr, Ca, and Ba are all elements of group 2a. Hence, these elements are arranged in order of increasing $IE_{1}$ as follows.

Ba < Sr < Ca

3 0

3 years ago

Element used in bright flashlights

Mazyrski [523]

The element would be Neon. They are found in signs

8 0

4 years ago