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3 years ago

A) total time taken for journeyb) the acceleration during the first part of the journey

Physics

1 answer:

borishaifa [10]3 years ago

4 0

Explanation:

a. the total time taken for the journey is 50sec.

b. u=0, v=10m/sec, t=20sec.

a=(v-u)/t = (10-0)/20 = 10/20 = 0.5 m/s².

hope this helps you to solve the problem.

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A 3.42 kg mass hanging vertically from a spring on the Earth (where g = 9.8 m/s2) undergoes simple oscillatory motion. If the sp

sineoko [7]

Answer:

Time period of oscillation on moon will be equal to 3.347 sec

Explanation:

We have given mass which is attached to the spring m = 3.42 kg

Spring constant K = 12 N/m

We have to find the period of oscillation

Period of oscillation is equal to $T=2\pi \sqrt{\frac{m}{K}}$ , here m is mass and K is spring constant

So period of oscillation $T=2\times 3.14\times \sqrt{\frac{3.42}{12}}$

$T=2\times 3.14\times 0.533=3.347sec$

So time period of oscillation will be equal to 3.347 sec

As it is a spring mass system and from the relation we can see that time period is independent of g

So time period will be same on earth and moon

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3 years ago

Under what environmental conditions are you most likely to generate static electricity?

pogonyaev

Mostly when your around carpet or anything related to a carpet because when you do it long enough you will generate static electricity i hope this helps

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3 years ago

The table below shows two types of electromagnetic waves and three random applications of electromagnetic waves.

Musya8 [376]

Answer:

a. Microwaves—3 and infrared waves—1

Explanation:

Microwaves and infrared waves are both part of the electromagnetic spectrum, but they have different frequency and wavelength.

In particular:

- Microwaves are long-wavelength electromagnetic waves, with wavelength between 1 mm and 1 m. Their wavelength is longer than visible light

- Infrared waves are also long-wavelength electromagnetic waves, but their wavelength is shorter than microwaves: between 700 nm and 1 mm. Their wavelength is also longer than visible light.

The two types of waves are also used for different purposes. In particular:

- Infrared waves are emitted by any hot object, and their intensity depends on the temperature of the object. Therefore, they are used in astronomy to show the heat released by astronomical objects (option 1)

- Microwaves are used to study the Cosmic Microwave Background (CMB). This is electromagnetic radiation that permeates the whole universe, and its wavelength depends inversely on the local temperature. Therefore, areas with longer wavelength have lower temperature, and viceversa. Therefore, microwaves are used to measure temperature differences in space (option 3).

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3 years ago

A brick is released with no initial speed from the roof of a building and strikes the ground in 1.80 s , encountering no appreci

Mars2501 [29]

<span>Kinematics is used in this problem. The mass does not matter here because the question is mass independent. vi = 0 vf = x d = ? d = vi + 1/2 a t^2 d = 0 + 1/2 (9.8) (1.8)^2 d = 15.9 m (counting sig figs)</span>

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4 years ago

Q C Blaise Pascal duplicated Torricelli's barometer using a red Bordeaux wine, of density 984kg/ m³ , as the working liquid (Fig

levacccp [35]

The pressure within Earth's atmosphere is referred to as atmospheric pressure or barometric pressure. 10.701 was the height h of the wine column for normal atmospheric pressure.

<h3>What is Atmospheric pressure?</h3>

The pressure within Earth's atmosphere is referred to as atmospheric pressure or barometric pressure. The definition of the standard atmosphere is 101,325 Pa, or the same as 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.

The force per unit area that an atmospheric column exerts is known as atmospheric pressure, often known as barometric pressure (that is, the entire body of air above the specified area). A weather indicator is atmospheric pressure. There will typically be clouds, wind, and precipitation when a low-pressure system enters a region. Fair, quiet weather is frequently a result of high pressure systems.

We have the density for the red Bordeaux wine given $\rho=965 \frac{\mathrm{kg}}{\mathrm{m}^3}$ , the atmospheric pressure on the Torricelli's barometer is given by:

$P_{a t m}=\rho g h$

Solving for the height of wine in the column we have this:

$h=\frac{P_{\text {anm }}}{\rho g}$

And replacing we have:

$h=\frac{101300 \mathrm{~Pa}}{965 \frac{\mathrm{kg}}{\mathrm{m}^3 9.81 \frac{\mathrm{m}}{\mathrm{m}^2}}}=10.701 \mathrm{~m}$$$

So the height of the red Bordeaux wine would be $\mathrm{h}=10.701 \mathrm{~m}$ . A very high value on this case if we compare with the usual values for this variable.

To learn more about Atmospheric pressure refer to:

brainly.com/question/19587559

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2 years ago

A) total time taken for journeyb) the acceleration during the first part of the journey​

A) total time taken for journeyb) the acceleration during the first part of the journey