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3 years ago

4. Distinguish where kinetic energy and potential energy are the greatest in the loop.

Chemistry

1 answer:

aksik [14]3 years ago

4 0

Kinetic energy is the energy from movement. Hence the fastest movement is at the bottom of the loop - therefore Kinetic energy is highest at the flat bottom of the loop.

Potential energy is the opposite - it occurs at the top of the loop when the car moves the slowest

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Preliminary preformulation studies for a new candidate drug molecule does not include one of these

devlian [24]

Answer:

Pilot scale up

Explanation:

Preformulation studies are carried out on candidate drug molecules that show sufficient pharmacological promise in animal model(pharma approach).

It involves preliminary study of the properties of a drug which is considered a potentially active ingredient against a particular disease condition.

Scale-up is the term used to refer to the increase in the batch size of a product. This is only done after a drug has been proven successful against the target disease after extensive pilot studies.

Scale-up is the last operation carried out when a drug has passed through all stages. It is not included in preliminary preformulation studies

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3 years ago

A sample of gas has a volume of 125mL at 6.0 atm pressure. What will the new volume in mL be of the pressure is decreased to 0.2

Rasek [7]

The answer is 607 your welcomeee

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3 years ago

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Murljashka [212]

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3 years ago

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What is the periodic element symbol for gold?

Makovka662 [10]

Gold is Au on the periodic table

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4 years ago

Calculate the mass of each product formed when 84.3 g of silver sulfide reacts with excess hydrochloric acid: ag2s(s) + hcl(aq)

oee [108]

Answer:

48.75 g of AgCl

11.60 g of H₂S

Solution:

The Balance Chemical Equation is as follow,

Ag₂S + HCl → AgCl + H₂S

Calculate amount of AgCl produced,

According to equation,

247.8 g (1 mol) of Ag₂S produces = 143.32 g (1 mol) of AgCl

So,

84.3 g of Ag₂S will produce = X g of AgCl

Solving for X,

X = (84.3 g × 143.32 g) ÷ 247.8 g

X = 48.75 g of AgCl

Calculate amount of H₂S produced,

According to equation,

247.8 g (1 mol) of Ag₂S produces = 34.1 g (1 mol) of H₂S

So,

84.3 g of Ag₂S will produce = X g of H₂S

Solving for X,

X = (84.3 g × 34.1 g) ÷ 247.8 g

X = 11.60 g of H₂S

6 0

3 years ago