What is the cause of tides on Earth?

Mathematics

1 answer:

svlad2 [7]2 years ago

3 0

The moon’s gravitational pull

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HELP ME NO RANDOM ANSWERS

liberstina [14]

Answer:

still need it?...........

6 0

2 years ago

Let C be the positively oriented square with vertices (0,0), (1,0), (1,1), (0,1). Use Green's Theorem to evaluate the line integ

liq [111]

Answer:

1/2

Step-by-step explanation:

The interior of the square is the region D = { (x,y) : 0 ≤ x,y ≤1 }. We call L(x,y) = 7y²x, M(x,y) = 8x²y. Since C is positively oriented, Green Theorem states that

$\int\limits_C {L(x,y)} \, dx + {M(x,y)} \, dy = \int\limits^1_0\int\limits^1_0 {(Mx - Ly)} \, dxdy$

Lets calculate the partial derivates of M and L, Mx and Ly. They can be computed by taking the derivate of the respective value, treating the other variable as a constant.

Mx(x,y) = d/dx 8x²y = 16xy
Ly(x,y) = d/dy 7y²x = 14xy

Thus, Mx(x,y) - Ly(x,y) = 2xy, and therefore, the line ntegral is equal to the double integral

$\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy$

We can compute the double integral by applying the Barrow's Rule, a primitive of 2xy under the variable x is x²y, thus the double integral can be computed as follows

$\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy = \int\limits^1_0 {x^2y} |^1_0 \,dy = \int\limits^1_0 {y} \, dy = \frac{y^2}{2} \, |^1_0 = 1/2$

We conclude that the line integral is 1/2

4 0

2 years ago

Kala has been offered two 40 hour a week jobs. One job pays an hourly wage of $25 and 10% of all sales. The other job pays $20 a

bazaltina [42]

(40 * 25) + 0.10x = (40 * 20) + 0.20x
1000 + 0.10x = 800 + 0.20x
1000 - 800 = 0.20x - 0.10x
200 = 0.10x
200/0.10 = x
2000 = x <=== weekly sales must be $ 2000

3 0

3 years ago

Find the average rate of change of f(x) = 4x² – 3 from 3 to 9.

Lina20 [59]

Answer:

Step-by-step explanation:

Given:

$f(x) = 4x^2 - 3$