2 years ago

Ký hiệu của vật liệu cơ khí

Engineering

1 answer:

USPshnik [31]2 years ago

4 0

Answer:

by hìuuf5ëcz

Explanation:

6tgiïuggd

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Calculate the volume of a hydraulic accumulator capable of delivering 5 liters of oil between 180 and 80 bar, using as a preload

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2) $V_o = 12.26 liters$

Explanation:

For isothermal process n =1

$V_o =\frac{\Delta V}{(\frac{p_o}{p_1})^{1/n} -(\frac{p_o}{p_2})^{1/n}}$

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correction factor for calculate dpressure ration for isothermal process is

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b) for adiabatic process

n =1.4

volume of hydraulic accumulator is given as

$V_o =\frac{\Delta V}{[\frac{p_o}{p_1}]^{1/n} -[\frac{p_o}{p_2}]^{1/n}}$

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