The magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.
Explanation:
The magnetic field strength at the center of a current-carrying circular loop is
where
is the vacuum permeability
I is the current
R is the radius of the loop
For the first circular loop, we have
The second loop has
(same current)
(twice the radius)
So, the magnetic field at the centre of the second loop is
So, the magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.
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Answer:
30Km/h
Explanation:
acceleration is the change of speed in a given time so when we substract the accelerations we can know how much the car goes per an hour
Answer:
x ’= 368.61 m, y ’= 258.11 m
Explanation:
To solve this problem we must find the projections of the point on the new vectors of the rotated system θ = 35º
x’= R cos 35
y’= R sin 35
The modulus vector can be found using the Pythagorean theorem
R² = x² + y²
R = 450 m
we calculate
x ’= 450 cos 35
x ’= 368.61 m
y ’= 450 sin 35
y ’= 258.11 m
D=-5m
a(gravity)=-9.8m/s^2
vi= 0m/s
t=?
use equation d=vi*t+0.5a*t^2
because vi=0, you can cross out vi*t because anything multiplied by 0= 0
rearrange the equation to say t^2=d/0.5a
t^2= -5/-4.9
t^2=1.02
find the square root...
final answer: t=1s
