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Physics

1 answer:

vova2212 [387]2 years ago

7 0

Answer:

Neutral

Explanation:

A neutral atom has an equal number of protons and electrons so that the positive and negative charges exactly balance. Since it is the electrons that determine how one atom interacts with another, in the end it is the number of protons in the nucleus that determines the chemical properties of an atom.

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Element A and element B have bonded and formed compound AB. Which of the following statements is true? Compound AB has chemical

creativ13 [48]

The correct answer from the choices listed above is the first option. The statement that is true would be that c<span>ompound AB has chemical and physical properties that are completely different from those of A and B. They completely different substances with different properties.</span>

6 0

3 years ago

Read 2 more answers

Two rams run toward each other. One ram has a mass of 49 kg and runs west

olga nikolaevna [1]

Answer: (d)

Explanation:

Given

Mass of the first ram $m_1=49\ kg$

The velocity of this ram is $v_1=-7\ m/s$

Mass of the second ram $m_2=52\ kg$

The velocity of this ram $v_2=9\ m/s$

They combined after the collision

Conserving the momentum

$\Rightarrow m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow 49\times (-7)+52\times (9)=(52+49)v\\\Rightarrow v=\dfrac{125}{101}\ m/s \quad[\text{east}]$

Momentum after the collision will be

$\Rightarrow 101\times \dfrac{125}{101}=125\ kg-m/s\ \text{East}$

Therefore, option (d) is correct

4 0

3 years ago

There is a basketball with a diameter of 9in. and a softball with a diameter of 4in. Find how many times greater the volume of t

erica [24]

Answer: #.37 times greater

Explanation: Volume of a sphere is: V = $\frac{4}{3}$ ·π·r³

Since it is given the diameter of the basketball and the softball, their ratios are r₁ = 3in and r₂ = 2in, in which index 1 represents the basketball and index 2, the softball.

Calculating the volume of basketball:

V₁ = $\frac{4}{3}$ . 3.14 . 3³

V₁ = 113.04 in³

Calculating the volume of softball:

V₂ = $\frac{4}{3}$ . 3.14 . 2³

V₂ = 33.5 in³

Comparing one volume with the other:

$\frac{V1}{V2}$ = $\frac{113.04}{33.5}$ = 3.37