What is the overall (X-fold) dilution of 4 serial 2-fold dilutions?

Chemistry

1 answer:

svet-max [94.6K]3 years ago

6 0

Answer:

16-fold dilution.

Explanation:

A serial dilution is any dilution where the concentration decrease by the same quantity in each successive step. So, for a 2-fold dilution, the concentration decrease 1/2, it means that if we have a sample with 10 M of concentration, after a 2-fold dilution it will be 5 M. For the next step it will be 1/2 of 5= 2.5 M, and successively.

Then, we just multiply the factor for each dilution. After 4 serial dilutions:

1/2 x 1/2 x 1/2 x 1/2 = 1/16

So, it would be a 16-fold dilution in the end.

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<h3>Answer:</h3>

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<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

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Molarity = moles of solute / liters of solution

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<u>Step 1: Define</u>

[Given] 2.14 moles (CH₃)₂SO

[Given] 2.00 L

[Solve] Molarity

<u>Step 2: Solve</u>

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Explanation:

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