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irga5000 [103]
3 years ago
6

Lead (II) nitrate and magnesium iodide solutions are mixed

Chemistry
1 answer:
sashaice [31]3 years ago
5 0

The molecular equation :

MgI₂(aq) + Pb(NO₃)₂(aq) → Mg(NO₃)₂(aq) + PbI₂(s)

The net ionic equations

Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)

<h3>Further explanation</h3>

Given

Word equation

Required

The molecular equations and  the net ionic equations

Solution

The chemical equation can be expressed in terms of:

  • word equation
  • skeleton equation
  • balanced equation

The equation of a chemical reaction can be expressed in the equation of the ions

When a spectator ions are removed, the ionic equation is called the net ionic equation

A molecular equation is a chemical equation that has been balanced and is written in molecular (not ionic) form

The molecular equation :

MgI₂(aq) + Pb(NO₃)₂(aq) → Mg(NO₃)₂(aq) + PbI₂(s)

the ionic equation :

Mg²⁺ +2I⁻ + Pb²⁺ + 2NO₃⁻ → Mg²⁺ + 2NO₃⁻ + PbI₂

the net ionic equations

Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)

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Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
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Answer:

  • <u>79%</u>

Explanation:

<u>1) Balanced chemical equation:</u>

  • 2S + 3O₂ → 2SO₃

<u>2) Mole ratio:</u>

  • 2 mol S : 3 mol O₂ : 2 mol SO₃

<u>3) Limiting reactant:</u>

  • Number of moles of O₂

        n = 6.0 g / 32.0 g/mol = 0.1875 mol O₂

  • Number of moles of S:

         n = 7.0 g / 32.065 g/mol = 0.2183 mol S

  • Ratios:

        Actual ratio: 0.1875 mol O₂ / 0.2183 mol S =0.859

        Theoretical ratio: 3 mol O₂ / 2 mol S = 1.5

Since there is a smaller proportion of O₂ (0.859) than the theoretical ratio (1.5), O₂ will be used before all S be consumed, and O₂ is the limiting reactant.

<u>4) Calcuate theoretical yield (using the limiting reactant):</u>

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<u>5) Yield in grams:</u>

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<u>6) </u><em><u>Percent yield:</u></em>

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